calling a function with struct inputs
显示 更早的评论
Hi,
How can I call such a function:
function varargout = hey(init,varargin)
if init ==1
if nargin >1
geom_gs = varargin{1};
m = geom_gs.box.m;
n = geom_gs.box.n;
Lx = geom_gs.box.Lx;
Ly = geom_gs.box.Ly;
end
end
end
1 个评论
"How can I call such a function"
Because it neither displays anything nor returns any output it is not a very interesting function to call.
But lets call it anyay:
S.box.m = 1;
S.box.n = 2;
S.box.Lx = 3;
S.box.Ly = 4;
hey(1,S)
function varargout = hey(init,varargin)
if init ==1
if nargin >1
geom_gs = varargin{1};
m = geom_gs.box.m;
n = geom_gs.box.n;
Lx = geom_gs.box.Lx;
Ly = geom_gs.box.Ly;
end
end
end
Note that VARARGIN can be replaced by a simple variable name.
Note that VARARGOUT is unused and can be removed.
采纳的回答
Pooja Kumari
2024-2-13
Hi,
To call the hey function, you would use the following syntax in MATLAB:
initValue = 1;
geom_gs.box.m = 10;
geom_gs.box.n = 20;
geom_gs.box.Lx = 100;
geom_gs.box.Ly = 200;
hey(initValue, geom_gs)
You have not returned anything from the "hey" function, so you can change the function and return the values to the "varargout"
You can refer below for the updated code:
function varargout = hey(init,varargin)
if init == 1
if nargin > 1
geom_gs = varargin{1};
m = geom_gs.box.m;
n = geom_gs.box.n;
Lx = geom_gs.box.Lx;
Ly = geom_gs.box.Ly;
% Assign to varargout
varargout{1} = m;
varargout{2} = n;
varargout{3} = Lx;
varargout{4} = Ly;
end
end
end
To call the hey function, you would use the following syntax in MATLAB:
[m,n,Lx,Ly] = hey(initValue, geom_gs)
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