Array indices must be positive integers or logical values.

Hey, I m trying to do a bissecion method code.
But when trying to give a var fa the value of f(a) it gives me a :'Array indices must be positive integers or logical values.'
Could anyone explain me why please ?
clear;
tol = 10^(-6);
x1= -2:0.01:2;
fx = x1.^2-1-sin(x1);
a=input('Intervalo inferior: ');
b=input('Intervalo superior: ');
fa=fx(a);
Array indices must be positive integers or logical values.
fb=fx(b);
if sign(fa)==sign(fb)
disp('no tiene solucion')
return
end
while (b-a)/2 > tol
c = (a+b)/2;
fc= fx(c);
if sign(a)==sign(c)
a=c;
fa=fc;
else
b=c;
fb=fc;
end
end
c

2 个评论

a and b are not constrained to being positive nonzero integers, so you can't use them as array indices.
yeah but they can be negative too, the roots are in between [-1;0] and [1;2]

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 采纳的回答

fx = @(X) X.^2-1-sin(X);

3 个评论

It works thanks a lot !
So the @(X) allows you to be able to give to X every variable you want right ?
Yes. In other words, it makes fx a function (or more precisely a function handle).

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更多回答(1 个)

Matlab arrays are indexed using whole integers, when you give a fractional or decimal values as input it throws such errors
clear;
tol = 10^(-6);
x1= -2:0.01:2;
fx = x1.^2-1-sin(x1)
fx = 1×401
3.9093 3.8735 3.8378 3.8023 3.7668 3.7315 3.6962 3.6611 3.6260 3.5911 3.5563 3.5216 3.4870 3.4525 3.4181 3.3838 3.3496 3.3155 3.2815 3.2476 3.2138 3.1802 3.1466 3.1131 3.0798 3.0465 3.0133 2.9803 2.9473 2.9144
a=2.7 %input('Intervalo inferior: ');
a = 2.7000
b=3.2 %input('Intervalo superior: ');
b = 3.2000
fa=fx(round(a)) % round the input values
fa = 3.8378
clear;
tol = 10^(-6);
x1= -2:0.01:2;
fx = x1.^2-1-sin(x1)
fx = 1×401
3.9093 3.8735 3.8378 3.8023 3.7668 3.7315 3.6962 3.6611 3.6260 3.5911 3.5563 3.5216 3.4870 3.4525 3.4181 3.3838 3.3496 3.3155 3.2815 3.2476 3.2138 3.1802 3.1466 3.1131 3.0798 3.0465 3.0133 2.9803 2.9473 2.9144
a=2.5; %input('Intervalo inferior: ');
b=3.2; %input('Intervalo superior: ');
fa=fx(a)
Array indices must be positive integers or logical values.

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