How can I convert indices into a binary matrix?

2 次查看(过去 30 天)
Hello all, I have a txt file that includes list of selected items (there are 10 items in total). I am reading the file using "readmatrix". I want to create a binary (logical) matrix as in the example below but I am getting "The subscript vectors must all be of the same size." message. How can I fix it? Thanks for the help.
1,3,5 -> 1,0,1,0,1,0,0,0,0,0
1,2,3,7 -> 1,1,1,0,0,0,1,0,0,0
1,2,6,7,8 -> 1,1,0,0,0,1,1,1,0,0
1,2,3 -> 1,1,1,0,0,0,0,0,0,0
...

采纳的回答

Dyuman Joshi
Dyuman Joshi 2024-2-18
编辑:Dyuman Joshi 2024-2-18
ItemSet = readmatrix('Test.txt','NumHeaderLines',0)
ItemSet = 31×7
1 5 9 10 NaN NaN NaN 1 5 9 10 NaN NaN NaN 1 5 8 9 10 NaN NaN 1 5 7 9 10 NaN NaN 3 5 9 10 NaN NaN NaN 3 5 8 9 10 NaN NaN 3 5 7 9 10 NaN NaN 3 4 5 9 10 NaN NaN 3 4 5 8 9 10 NaN 3 4 5 7 9 10 NaN
tic
s = size(ItemSet);
%corresponding row values
row = repelem((1:s(1)).', 1, s(2))
row = 31×7
1 1 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 3 3 3 4 4 4 4 4 4 4 5 5 5 5 5 5 5 6 6 6 6 6 6 6 7 7 7 7 7 7 7 8 8 8 8 8 8 8 9 9 9 9 9 9 9 10 10 10 10 10 10 10
%maximum value
m = max(ItemSet, [], 'all');
%subscript values
idx = [row(:) ItemSet(:)];
%check for NaN values
k = isnan(idx(:,2));
out = accumarray(idx(~k,:), 1, [s(1) m])
out = 31×10
1 0 0 0 1 0 0 0 1 1 1 0 0 0 1 0 0 0 1 1 1 0 0 0 1 0 0 1 1 1 1 0 0 0 1 0 1 0 1 1 0 0 1 0 1 0 0 0 1 1 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 0 1 0 1 1 0 0 1 1 1 0 0 0 1 1 0 0 1 1 1 0 0 1 1 1 0 0 1 1 1 0 1 0 1 1
toc
Elapsed time is 0.010489 seconds.

更多回答(1 个)

Alexander
Alexander 2024-2-18
Maybe something like the following?
fid = fopen('Item.txt');
A = [];
while(~feof(fid))
syLine = fgetl(fid);
dyA = zeros(1,10);
syLine = ['[' syLine ']'];
dyLine = eval(syLine);
dyA(dyLine) = 1;
A = [A; dyA];
end
A
fclose(fid)
  3 个评论

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

产品


版本

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by