Combining two arrays using a seconds order

Question

Fatih 2024-2-18

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2083508-combining-two-arrays-using-a-seconds-order

评论： Fatih 2024-2-20

采纳的回答： Matt J

I have two arrays.

number = [8 9 4 1 2 3 6 7 10 5]

number2 = [5 1 6 7 3 4 10 9 8 2]

I would like to replace the first 5 values of number (8 9 4 1 2)

with the same order for these values in number2 (1 4 9 8 2). So the revised number will be [1 4 9 8 2 3 6 7 10 5] as the next five numbers will not change.

Thanks in advance

2 个评论
显示无隐藏无

Rik 2024-2-18

Should it only be the first 5 values?

You can use the ismember function to do this. What have you tried so far?

Fatih 2024-2-18

thanks, meanwhile I used exactly what you mentioned. The following code worked for me.

++

number = randperm(10, 10)

number2 = randperm(10, 10)

[tf, loc] = ismember(number(1:5), number2)

loc2 = sort(loc)

number = [number2(loc2) number(6:10)]

++

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Matt J 2024-2-18

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2083508-combining-two-arrays-using-a-seconds-order#answer_1411213

编辑：Matt J 2024-2-18

在 MATLAB Online 中打开

number  = randperm(10, 10)
number = 1x10
    10     5     4     3     1     9     8     6     2     7
number2 = randperm(10, 10)
number2 = 1x10
     8     6     5     3     7    10     2     1     4     9
I=ismember(number2,number(1:5));
number(1:5)=number2(I)
number = 1x10
     5     3    10     1     4     9     8     6     2     7