I am trying to assign a new set of alphabets to a strand of alphabet matrix that I already have

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SANGBIN LEE 2024-2-20

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https://ww2.mathworks.cn/matlabcentral/answers/2084173-i-am-trying-to-assign-a-new-set-of-alphabets-to-a-strand-of-alphabet-matrix-that-i-already-have

回答： sai charan sampara 2024-2-26

insulinDNAseq.txt

B = {'a' 'u'
    'c' 'g'
    'g' 'c'
    't' 'a'};
for i = 1:length(template3_5)
    DNA_base = [];
    row_B = strcmp(DNA_base,B(:,1));
    RNA_base = [];
    [];
end

template 3_5 is supposed to be the sequence text attached. I am supposed to write a code and modify the parts in [];. Using the matrix B, I have to assign a new set of alphabets to the current template(text file) that I have.

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SANGBIN LEE 2024-2-20

@Stephen23 i have to modify the for loop in order to get the alphabet strand from the text file to match up and transition into a new sequence of alphabets based on the matrix B. so for example, if i have a 'a', it should match up with 'u', 'c' shoudl match with 'g' so on.

Stephen23 2024-2-20

编辑：Stephen23 2024-2-20

在 MATLAB Online 中打开

"i have to modify the for loop in order to get the alphabet strand from the text file to match up and transition into a new sequence of alphabets based on the matrix B. so for example, if i have a 'a', it should match up with 'u', 'c' shoudl match with 'g' so on."

No, that is your task or goal. What is your question? So far you have not asked us anything.

I have to go to Beijing. How do I get to Beijing?
^^^^ GOAL/TASK ^^^^^^^^  ^^^^^^^ QUESTION ^^^^^^^

There are many things that you might be trying to ask, but making us guess is not an efficient way to transfer this information.

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Answer 1

sai charan sampara 2024-2-26

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2084173-i-am-trying-to-assign-a-new-set-of-alphabets-to-a-strand-of-alphabet-matrix-that-i-already-have#answer_1416598

在 MATLAB Online 中打开

insulinDNAseq.txt

Hello Lee,

I understand that you are trying to replace every letter of the sequence by a specific letter based on the mapping given by the matrix.

You have mentioned that “template3_5” is the sequence attached. It can be defined by opening the text file using “fopen” and reading its content as a string using “fscanf”. Then in the “for” loop each letter can be accessed as “DNA_base” and compared with the matrix to find the suitable mapping. From the mapping, the corresponding “RNA_base” can be found out. These “RNA_base” can be put together to form the required complete sequence. It can be done as follows:

seq_file = fopen('insulinDNAseq.txt');
template3_5 = fscanf(seq_file,'%s')
template3_5 = 'gctggttcaagggctttattccatctctctcggtgcaggaggcggcgggtgtggggctgcctgcgggctgcgtctagttgcagtagttctccagctggtagagggagcagatgctggtacagcattgttccacaatgccacgcttctgcagggacccctccagggccaagggctgcaggctgcctgcaccagggcccccgcccagctccacctgccccacctgcaggtcctctgcctcccggcgggtcttgggtgtgtagaagaagcctcgttccccgcacactaggtagagagcttccaccaggtgtgagccgcacaggtgttggttcacaaaggctgcggctgggtcaggtccccagagggccagcagcgccagcaggggcaggaggcgcatccacagggccatggcagaaggacagtgatctgcttgatggcctcttctgatgcagcctgtcctggagggct'
B = {'a' 'u'
    'c' 'g'
    'g' 'c'
    't' 'a'};
RNA='';
for i = 1:length(template3_5)
    DNA_base = template3_5(i);
    row_B = strcmp(DNA_base,B(:,1));
    RNA_base = B{row_B,2};
    RNA(i)=RNA_base;
end
RNA
RNA = 'cgaccaaguucccgaaauaagguagagagagccacguccuccgccgcccacaccccgacggacgcccgacgcagaucaacgucaucaagaggucgaccaucucccucgucuacgaccaugucguaacaagguguuacggugcgaagacgucccuggggaggucccgguucccgacguccgacggacguggucccgggggcgggucgagguggacgggguggacguccaggagacggagggccgcccagaacccacacaucuucuucggagcaaggggcgugugauccaucucucgaaggugguccacacucggcguguccacaaccaaguguuuccgacgccgacccaguccaggggucucccggucgucgcggucguccccguccuccgcguaggugucccgguaccgucuuccugucacuagacgaacuaccggagaagacuacgucggacaggaccucccga'