define function in one line

28 次查看（过去 30 天）
fumio hakamada
fumio hakamada 2024-2-23
评论： Rik 2024-2-23
How can I define vector p without using function statement?
suppose
t = 0:0.1:1
p = sin(t) when t<0.6
p = 0 when t>=0.6
  2 个评论
DGM
DGM 2024-2-23
编辑：DGM 2024-2-23
Ran in:
What's wrong with just
t = 0:0.1:1;
p = sin(t).*(t<0.6);
plot(t,p)
... of course, the range and resolution of t makes this plot appear a bit unclear.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Rik
Rik 2024-2-23
Ran in:
I don't know if you want to avoid anonymous functions as well, but this should give you a finer plot:
% p = sin(t) when t<0.6
% p = 0 when t>=0.6
p = @(t) (t<0.6).*sin(t);
fplot(p,[0 1])
The problem here is mostly that sin(x) is very close to x for small x, which means you have a fairly straight line. Adding a straight line helps to show there is actually a slight curve:
p = @(t) (t<0.6).*sin(t);
figure
fplot(p,[0 1])
hold on
fplot(@(t) sign(p(t)).*t,[0 1])
legend({'y = sin(t)','y = x'})
  2 个评论
fumio hakamada
fumio hakamada 2024-2-23
移动：Rik 2024-2-23
I had no idea about logical vector and usage of ".*". Thanks for both of you.
Rik
Rik 2024-2-23
You're welcome. If my answer solved your issue, please consider marking it as accepted.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Programming 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by