How to plot graph regarding the definite integral by using Midpoint rule for the function 𝑦 =x^1/3?

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This is what I have done and I'm not sure is it correct.
I don't know how to continue to plot the graph of it.
y = @(x) nthroot(x,3); %Function to integrate
a = 0; b = 2; %Interval where a is the lower boundary and b is the upper boundary.
n = 10; %Number of subintervals
dx = (b-a/n); %Width of each rectangle
mpr = 0;
for i = a:dx:b
mpr = mpr + f(i+dx/2);
end
I = dx*mpr;
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Hassaan
Hassaan 2024-3-6
编辑:Hassaan 2024-3-6
% Define the function to integrate using a function handle
f = @(x) nthroot(x,3);
% Define the interval and the number of subintervals
a = 0; b = 2; % Interval [a, b]
n = 10; % Number of subintervals
% Calculate the width of each subinterval
dx = (b - a) / n;
% Initialize the midpoint sum
mpr = 0;
% Calculate the sum for the Midpoint Rule
for i = 1:n
xi = a + (i-0.5)*dx; % Midpoint of the i-th subinterval
mpr = mpr + f(xi); % Add the value at the midpoint
end
% Calculate the integral approximation
I = dx * mpr;
% Display the result
fprintf('The approximate value of the integral is: %f\n', I);
The approximate value of the integral is: 1.896224
% Plotting the function and the rectangles
x_vals = linspace(a, b, 1000); % Generate 1000 points between a and b
y_vals = arrayfun(f, x_vals); % Evaluate the function at each x value
% Plot the function
plot(x_vals, y_vals, 'b-', 'LineWidth', 1.5);
hold on; % Hold on to the current plot
% Plot each rectangle
for i = 1:n
xi = a + (i-0.5)*dx; % Midpoint of the i-th subinterval
% Plot the rectangle
rect_x = [xi - dx/2, xi - dx/2, xi + dx/2, xi + dx/2];
rect_y = [0, f(xi), f(xi), 0];
patch(rect_x, rect_y, 'r', 'EdgeColor', 'r', 'FaceAlpha', 0.1);
end
% Formatting the plot
xlabel('x');
ylabel('y');
title('Midpoint Rule Approximation');
legend('y = nthroot(x, 3)', 'Midpoint rectangles');
hold off; % Release the plot hold
MATLAB Learning Material:
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