How to solve this problem?

2024 3 6
1 个回答
更新时间：2024 3 7
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0 个投票

Suppose I have an array that is a large m x n matrix. For a value y, if the numbers in this matrix are less than y, then i want to replace those values with 0, otherwise they are 1. how to compute this? I have written a rudimentary code, but i need help.
df = xlsread("Book1.xlsx");
for i = 1:448 %448 = number of columns
x = df(:,i)
if x < 40
x = 0
else
x = 1
i = i + 1
end
end

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回答（1 个）

Voss
Voss 2024-3-6
Ran in:

0 个投票

Ran in:
y = 0.3;
df = rand(3,4) % random matrix
df = 3×4
0.0521 0.9094 0.8965 0.7698 0.1742 0.3911 0.7067 0.1376 0.8626 0.0311 0.2910 0.0843
df = double(df >= y)
df = 3×4
0 1 1 1 0 1 1 0 1 0 0 0

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Arpita
Arpita
2024-3-6

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Voss
Voss
2024-3-7

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