How to solve this problem?

2 次查看（过去 30 天）

Arpita 2024-3-6

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2091366-how-to-solve-this-problem

评论： Voss 2024-3-7

Suppose I have an array that is a large m x n matrix. For a value y, if the numbers in this matrix are less than y, then i want to replace those values with 0, otherwise they are 1. how to compute this? I have written a rudimentary code, but i need help.

df = xlsread("Book1.xlsx");
for i = 1:448 %448 = number of columns
    x = df(:,i)
    if x < 40
        x = 0
    else
        x = 1
        i = i + 1
    end
end

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Voss 2024-3-6

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2091366-how-to-solve-this-problem#answer_1422111

在 MATLAB Online 中打开

y = 0.3;
df = rand(3,4) % random matrix
df = 3×4
    0.0521    0.9094    0.8965    0.7698
    0.1742    0.3911    0.7067    0.1376
    0.8626    0.0311    0.2910    0.0843
df = double(df >= y)
df = 3×4
     0     1     1     1
     0     1     1     0
     1     0     0     0