I keep getting the error using '/'.

3 次查看(过去 30 天)
"Error using /
Arguments must be numeric, char, or logical. "
I have a 64X1 matrix of vol_frac and particle_ratio each. 'c' goes from 1 to 64 using for loop. Please tell me what is going wrong and how to rectify it. I have tried writing "vf=vol_frac(c,1);" inside for loop so that vf isn't a matrix but still same problem.
mu_ratio=(1-(vol_frac(c,1)/0.605)*((particle_ratio(c,1))^1.2))^(-1.5125);
  2 个评论
Rik
Rik 2024-3-8
Try to make a MWE so we can run your code without any other dependencies and can reproduce your issue. The best way to do this is to use the code section in the editor and use the run button. That way you can make sure we will see the same error message as you do.
Adwait Mahajan
Adwait Mahajan 2024-3-8
The equation is under For loop so need to extract single value from vol_frac matrix. Don't want matrix division.

请先登录,再进行评论。

回答(2 个)

Alan Stevens
Alan Stevens 2024-3-8
Try
mu_ratio=(1-(vol_frac(c,1)/0.605).*((particle_ratio(c,1)).^1.2)).^(-1.5125);
Notice the dots! .* .^
Difficult to be certain though. You should upload enough program for us to test.
  3 个评论

请先登录,再进行评论。


VBBV
VBBV 2024-3-8
condition=readmatrix('cases.xlsx','Sheet',1,'Range','A2:C65');
  2 个评论
VBBV
VBBV 2024-3-8
use readmatrix function in place of readtable and run the code. The outputs from readtable are usually not numeric arrays

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

产品


版本

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by