how to do for loop 2nd level?

Question

Arif 2024-3-11

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2092896-how-to-do-for-loop-2nd-level

评论： Arif 2024-3-16

采纳的回答： Rik

hi guys, i want to do :

XY :

AA

AB

AC

AD

..

QQ

but this error happened.

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Arif 2024-3-11

Here is my code

clc

clear

beam = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'}

column = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'}

for i = 1 : length(beam)

x(i) = string(beam(i))

for j = 1 : length(column)

y(j) = string(column(j))

xy(i) = append(x(i),y(j))

end

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Answer 1

Rik 2024-3-11

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2092896-how-to-do-for-loop-2nd-level#answer_1423541

编辑：Rik 2024-3-11

在 MATLAB Online 中打开

Your code can be optimized, but here are the minimal changes.

beam = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'};
column = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'};
xy=repmat("",numel(beam)*numel(column),1);
k=0;
for i = 1 : numel(beam)
    x = string(beam(i));
    for j = 1 : numel(column)
        y = string(column(j));
        k=k+1;
        xy(k) = x+y;
    end
end
xy
xy = 289×1 string array
    "AA"
    "AB"
    "AC"
    "AD"
    "AE"
    "AF"
    "AG"
    "AH"
    "AI"
    "AJ"
    "AK"
    "AL"
    "AM"
    "AN"
    "AO"
    "AP"
    "AQ"
    "BA"
    "BB"
    "BC"
    "BD"
    "BE"
    "BF"
    "BG"
    "BH"
    "BI"
    "BJ"
    "BK"
    "BL"
    "BM"

Now for the more compact version (using implicit expansion and transposing with .'):

beam = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'};
column = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'};
xy = string(beam).'+string(column);
xy = xy(:);
xy
xy = 289×1 string array
    "AA"
    "AB"
    "AC"
    "AD"
    "AE"
    "AF"
    "AG"
    "AH"
    "AI"
    "AJ"
    "AK"
    "AL"
    "AM"
    "AN"
    "AO"
    "AP"
    "AQ"
    "BA"
    "BB"
    "BC"
    "BD"
    "BE"
    "BF"
    "BG"
    "BH"
    "BI"
    "BJ"
    "BK"
    "BL"
    "BM"

Or perhaps even this:

beam = string(num2cell('A':'Q'));
column = string(num2cell('A':'Q'));
xy = reshape(beam+column.',[],1);
xy
xy = 289×1 string array
    "AA"
    "AB"
    "AC"
    "AD"
    "AE"
    "AF"
    "AG"
    "AH"
    "AI"
    "AJ"
    "AK"
    "AL"
    "AM"
    "AN"
    "AO"
    "AP"
    "AQ"
    "BA"
    "BB"
    "BC"
    "BD"
    "BE"
    "BF"
    "BG"
    "BH"
    "BI"
    "BJ"
    "BK"
    "BL"
    "BM"