I am trying to solve the following problem and got stuck if you can give some guidance

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dareen 2024-3-16

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评论： Hassaan 2024-3-16

采纳的回答： Hassaan

Problem 713. Find the maximum number of decimal places in a set of numbers

Find the maximum number of decimal places in a set of numbers after decimal point that are significant

function y = find_max_sigdec(x)

y = max(max(length(rem(x,1))));

end

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dareen 2024-3-16

thank u much appreciated

dareen 2024-3-16

编辑：dareen 2024-3-16

what a save i dont understand how i missed this up so bad with length i figured something is wrong but kept changing the elements of a matrix of the same size and some how got really fitting answers 4 and the max was always 4 digits ,so when i used length it gave me the length of the matrix not the elements ,and the elements are not strings they are numebrs whatever i substitue has a length of 1 which is somehow confusing in other languages the length of the number was the num of digits it has so it seems like i have to change the input to a string to be able to deal with this the link you added really made the double precision topic more understandable thanks , i will try to learn more about strigns so that i can reach a solution of my own and just to check

if i want to fix the code is there a simpler approach that you would reccomend

thanks again @Dyuman Joshi

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采纳的回答

Hassaan 2024-3-16

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2095151-i-am-trying-to-solve-the-following-problem-and-got-stuck-if-you-can-give-some-guidance#answer_1426186

编辑：Hassaan 2024-3-16

在 MATLAB Online 中打开

Looks like a MATLAB Cody Problem. One of the many approaches that may exist:

x = [1.000 1.04 0.22 10.1;
  2.05 2.33 4.1 1000.31;
  5.00010 6.429 7.492 8.0];
y = find_max_sigdec(x)
y = 4
%y = find_max_sigdec(3.123456789)
disp(y)
     4
function y = find_max_sigdec(x)
    maxDecimals = 0; % Initialize the maximum number of decimal places
    x = x(:); % Linearize the matrix to iterate over all elements
    for i = 1:numel(x)
        % Extract the decimal part by subtracting the integer part
        decimalPart = abs(x(i) - floor(x(i)));
        if decimalPart > 0
            % Convert the decimal part to a string
            str = num2str(decimalPart);
            % Find the index of the decimal point
            idx = strfind(str, '.');
            % Calculate the number of significant decimal places
            numDecimals = length(str) - idx;
            % Update maxDecimals if this number is larger
            maxDecimals = max(maxDecimals, numDecimals);
        end
    end
    y = maxDecimals; % Return the maximum number of decimal places found
end

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dareen 2024-3-16

编辑：dareen 2024-3-16

thank u this was helpful ,and pardon me i will just wait for a while before accepting an answer so that there is a possibility to recive new comments or answers

Hassaan 2024-3-16