how can we do a fourier transform of continuos elliptical slip distribution?
2 次查看(过去 30 天)
显示 更早的评论
%% pescribing the elliptical slip distribution
% Define parameters
Lx = 100; % Length of the fault in x-direction
Nx = 512; % Number of points in x-direction
A = 1; % Maximum slip
a = 20; % Semi-major axis of the ellipse
x0 = Lx / 2; % x-coordinate of the center of the ellipse
% Create spatial grid
x = linspace(0, Lx, Nx);
% Define elliptical slip distribution along x-axis
slip_distribution = A * sqrt(1 - ((x - x0).^2 / a^2));
% Plot the slip distribution
figure
plot(x, slip_distribution, 'LineWidth', 2);
xlabel('X');
ylabel('Slip');
title('1D Elliptical Slip Distribution');fault
回答(1 个)
Hassaan
2024-3-17
% Define parameters
Lx = 100; % Length of the fault in x-direction
Nx = 512; % Number of points in x-direction
A = 1; % Maximum slip
a = 20; % Semi-major axis of the ellipse
x0 = Lx / 2; % x-coordinate of the center of the ellipse
% Create spatial grid
x = linspace(0, Lx, Nx);
% Define elliptical slip distribution along x-axis, limiting to non-negative values
slip_distribution = A * sqrt(max(1 - ((x - x0).^2 / a^2), 0));
% Plot the slip distribution
figure;
plot(x, slip_distribution, 'LineWidth', 2);
xlabel('X');
ylabel('Slip');
title('1D Elliptical Slip Distribution');
-----------------------------------------------------------------------------------------------------------------------------------------------------
If you find the solution helpful and it resolves your issue, it would be greatly appreciated if you could accept the answer. Also, leaving an upvote and a comment are also wonderful ways to provide feedback.
It's important to note that the advice and code are based on limited information and meant for educational purposes. Users should verify and adapt the code to their specific needs, ensuring compatibility and adherence to ethical standards.
Professional Interests
- Technical Services and Consulting
- Embedded Systems | Firmware Developement | Simulations
- Electrical and Electronics Engineering
Feel free to contact me.
0 个评论
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!