Draw a triangle in image knowing its center of gravity

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jan
jan 2015-4-17
评论： Image Analyst 2015-4-17
i need to draw a white triangle in a black image. So the first idea that i had got is to define the three peaks that define the triangle and then recuperate the points that belong to its surface. and then affect the value 1 to these points in a black image. To recuperate the points belong to the surface of the triangle i write this code which reflects the idea that a point belongs to a plan it verifies an equation system like after: ( the plane will be the triangle)
if true
k=1;
for i=1:size_image_x
for j=1:size_image_y
equation_x=i-x_peak1==xk*(x_peak2-x_peak1)+yk*(x_peak3-x_peak1);
equation_y=j-y_peak1==xk*(y_peak2-y_peak1)+yk*(y_peak3-y_peak1);
eqx=solve(equation_x,xk,yk);
eqy=solve(equation_y,xk,yk);
if isempty(eqx)~=1 && isempty(eqy)~=1
point_x(1,k)=i;
point_y(1,k)=j;
k=k+1;
end
end
end
end
but it doesn't work
may any one help me please
thanks

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采纳的回答

Image Analyst
Image Analyst 2015-4-17
Way too complicated. Simply use poly2mask() and do it all in one line of code:
mask = poly2mask([x_peak1, x_peak2, x_peak3], [y_peak1, y_peak2, y_peak3], size_image_y, size_image_x);
  2 个评论
jan
jan 2015-4-17
okay thanks a lot it is a very good and simple solution you are right. do you have any other solution if we don't have the three peaks of the triangle but we have its center of gravity????
Image Analyst
Image Analyst 2015-4-17
You need something else, like the radius and angle to one of the vertices or something. Obviously you could just spin a triangle around the center of gravity and they would all be triangles, just at different orientations. It's just a matter of simple trigonometry to get the three vertices once you have enough other information. What orientation do you want to draw it at? Surely you must have SOME idea.

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