インデックスが配列要素数を超えています。インデックスは 0 を超えてはなりません。
66 次查看(过去 30 天)
显示 更早的评论
syms s
for kq = -10:1:10
eqnqroop = 1 + (kq*(-((4483*s^3)/5000 + (1915281*s^2)/5000000 - (551896897*s)/5000000000)/(s^4 + (52*s^3)/125 ...
+ (764541*s^2)/1000000 + (4137177603*s)/500000000 - 427810011/250000000))) == 0;
q1 = solve(eqnqroop,s); %%求解
kq
plot(real(q1(1)),imag(q1(1)),'-s','MarkerSize',5,'MarkerEdgeColor','red', 'MarkerFaceColor',[1 .6 .6])
hold on
end
kqを-10~10まで1刻みで変えながら,eqnqroopという方程式の解を複素平面にプロットする,ということをしたいのですが,「インデックスが配列要素数を超えています。インデックスは 0 を超えてはなりません。」とでてきてしまい,-10~0までで計算がストップしてしまいます.
解決方法をご教授いただけると幸いです.
0 个评论
采纳的回答
Dyuman Joshi
2024-3-28
编辑:Dyuman Joshi
2024-3-28
When kq is 0, the equation becomes 1==0, which is obviously not true, thus there is no solution for it. For that iteration, q1 is empty and you can't use indexing for it.
You can skip that value or plot a value manually for it. I have implemented the 1st option in my code below.
Note that the solve() returns the real solutions first if there are any. As the equation is a cubic polynomial in s, there will atleast be one real solution, so use the 2nd index for plotting.
syms s
figure
hold on
%Modify the loop indices to skip the value 0
for kq = setdiff(-10:10, 0)
eqnqroop = 1 + (kq*(-((4483*s^3)/5000 + (1915281*s^2)/5000000 - (551896897*s)/5000000000)/(s^4 + (52*s^3)/125 ...
+ (764541*s^2)/1000000 + (4137177603*s)/500000000 - 427810011/250000000))) == 0;
q1 = solve(eqnqroop,s);
%updated indexing
plot(real(q1(2)),imag(q1(2)),'-s','MarkerSize',5,'MarkerEdgeColor','red', 'MarkerFaceColor',[1 .6 .6])
end
2 个评论
Dyuman Joshi
2024-3-28
You're welcome!
If my answer solved your problem, please consider accepting the answer.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 ビッグ データの処理 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!