How i can the value for x y z by using a matrix

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calculate the values of the (x,y, and z) for the following 3*3 linear algebraic equation . Where the inputs are 𝑎1−3, 𝑏1−3, 𝑐1−3, 𝑎𝑛𝑑 𝑞1−3 𝑎𝑠 𝑣𝑒𝑐𝑡𝑜𝑟𝑠. 𝑂𝑟𝑔𝑖𝑛𝑎𝑙 𝑓𝑜𝑟𝑚 𝑜𝑓 𝑒𝑞𝑎𝑡𝑖𝑜𝑛𝑠 ∶ 𝑎1𝑥 + 𝑏1𝑦 + 𝑐1𝑧 = 𝑞1 𝑎2𝑥 + 𝑏2𝑦 + 𝑐2𝑧 = 𝑞2 𝑎3𝑥 + 𝑏3𝑦 + 𝑐3𝑧 = 𝑞3 Try the code by entering different values of vectors.

回答(1 个)

Gayatri
Gayatri 2024-4-2
Hi Abdul,
To solve the given system of linear equations 𝑎1𝑥 + 𝑏1𝑦 + 𝑐1𝑧 = 𝑞1, 𝑎2𝑥 + 𝑏2𝑦 + 𝑐2𝑧 = 𝑞2 and 𝑎3𝑥 + 𝑏3𝑦 + 𝑐3𝑧 = 𝑞3, use the ‘linsolve’ function.
function [x, y, z] = solveLinearEquations(a, b, c, q)
A = [a(1), b(1), c(1); a(2), b(2), c(2); a(3), b(3), c(3)];
Q = [q(1); q(2); q(3)];
solution = linsolve(A, Q);
x = solution(1);
y = solution(2);
z = solution(3);
end
Enter the different values for the coefficient vectors a, b, c and the constant vector q, then call the ‘solveLinearEquations’ function.
Please refer the below documentation for ‘linsolve’ function:
I hope it helps!

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