forrt1 severe (38) error

2015 4 18
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更新时间：2015 4 28
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hi i have an exacutable file when i run it with 2000 pixels of image i don't receice any error, but when i increase the number of pixels i receive the message: forrt1 severe (38) error. what does it mean? another question how much pixels i can use in analysis of it on matlab

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回答（1 个）

Geoff Hayes
Geoff Hayes 2015-4-18

1 个投票

masri - what is the executable that you are running? I'm guessing that it is a Fortran compiled MEX file which takes in some inputs and tries to write something to file which fails for the case where you are trying to run the program with more than 2000 pixels (do you mean that you input a value of 2000 or an image with 2000 or more pixels - please clarify). A quick Google search reveals that this error can be generated during a file write operation.
It may be that the Fortran code used that the program is compiled makes certain assumptions about the inputs. If you have the code then you should try and figure out what those assumptions are, or contact the author of the executable.

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masri hala
masri hala 2015-4-19
thank you for your answer. the executable is a program of segmentation of image under matlab. with 2000 pixels the program run correctly but with more pixels i receive the message that you knew. i need an answer beacause i want to apply my program on image 200x320. thanks
Geoff Hayes
Geoff Hayes 2015-4-19
masri - so the executable is MEX function compiled from Fortran code?
masri hala
masri hala 2015-4-20
yes as the message describe. do have a solution?
masri hala
masri hala 2015-4-20
hi do you have a solution for this type of problem?
Geoff Hayes
Geoff Hayes 2015-4-20
Masri - do you have the Fortran source code because that is what you will need to modify to account for your new requirements. If you don't have the code, then you will need to contact the author of the code.
masri hala
masri hala 2015-4-22
morning did you mean i need fortran source code only for big number of pixels only? because for a few number i don't have a problem, the algorithm was executed normally.
James Tursa
James Tursa 2015-4-22
If the function works for "small" number of pixels but crashes for "large" number of pixels, then there is likely some limitation in the code itself that is causing it, and likely the only solution is to change the source code and re-compile the routine. The only way to tell for sure is to look at the source code and/or contact the author.
masri hala
masri hala 2015-4-22
thanks for all. I will try to change the code.
masri hala
masri hala 2015-4-27
hi, i changed my code source and i tried to run my code . the last error was disappeared. now the problem is out of memory. what is the dimension of square matrix matlab can accept? is acceptable a matrix (20000,20000)? thank you. i hope read an answer.
James Tursa
James Tursa 2015-4-27
编辑：James Tursa 2015-4-27
Type the following at the command line to see your memory situation:
memory
The array you are trying to use is about 3GB.
masri hala
masri hala 2015-4-28
my question is that matlab can execute any size dimension of matrix?
James Tursa
James Tursa 2015-4-28
" ... any size ..." Clearly no, there is a finite amount of memory in your computer and MATLAB has limits. To see the current working limits type "memory" at the command line as advised.

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