To find answer using matlabfunction

Question

Navaneeth 2024-4-4，7:32

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2102751-to-find-answer-using-matlabfunction

评论： Navaneeth 2024-4-4，8:19

I am using matlabfunctions to try and solve for an equation for many possible variable combination, the script is executing but I am not sure it is what I am expecting.

Here is the program,

clear;clc;close all;
syms r1 r2 d ni
f = matlabFunction((ni-1).*((1./r1)-(1./r2)+(((ni-1).*d)./(ni.*r1.*r2))));
n = 100;
r1a = linspace(14.8e-3,15e-3,n);r2a = linspace(-14.8e-3,-15e-3,n);d = linspace(4e-3,4.1e-3,n);ni=linspace(1.51,1.518,n);
[R1,R2,D,N] = ndgrid(r1a,r2a,d,ni);
p = feval(f,R1,R2,D,N);
F = 1/p;
ind = find (F>0.014 & F<0.015);
Freq = F(ind);
r1req = R1(ind);I am 
r2req = R2(ind);
dreq = D(ind);
nreq = N(ind);
Ar = [Freq,r1req,r2req,dreq,nreq];

What I am expecting here is the different combinations of n, r1, r2, and d thar gives f in range of 0.014 to 0.015

I am getting values till p right but while calculation F as 1/p I am getting values that are different to what I am anticipating.

If I am looking for F for the values of r1 = 15e-3;r2 = -15e-3;d = 4.049e-3;ni=1.5168; with above code I am getting 0.002 but with below code it is 0.015

clc;clear;close all;
r1 = 15e-3;r2 = -15e-3;d = 4.049e-3;ni=1.5168;
p = (ni-1).*((1./r1)-(1./r2)+(((ni-1).*d)./(ni.*r1.*r2)));
f = 1/p;

So how to correct the top code to get accurate f values.

Any kind of help is highly appreciable.

Thank you and regards.

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Answer 1

Dyuman Joshi 2024-4-4，7:56

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2102751-to-find-answer-using-matlabfunction#answer_1436326

在 MATLAB Online 中打开

You get the wrong value because the order of inputs is not correct.

By default, matlabFunction uses alphabetical order for the input arguments when converting symbolic expressions that contain only lowercase letters for the variable names. (Reference - https://in.mathworks.com/help/symbolic/sym.matlabfunction.html#d126e256587)

syms r1 r2 d ni

You can see the order of input to be provided from the definition of the function handle as well -

f = matlabFunction((ni-1).*((1./r1)-(1./r2)+(((ni-1).*d)./(ni.*r1.*r2))))
f = function_handle with value:
    @(d,ni,r1,r2)(ni-1.0).*(1.0./r1-1.0./r2+(d.*(ni-1.0))./(ni.*r1.*r2))
n = 100;
r1 = 15e-3;
r2 = -15e-3;
d = 4.049e-3;
ni = 1.5168;
%Providing values in the correct order
p = feval(f,d,ni,r1,r2);
F = 1/p
F = 0.0152