Cannot run with provided input arguments

Question

Lakshmi 2024-4-4，15:59

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2102991-cannot-run-with-provided-input-arguments

评论： Voss 2024-4-4，19:11

Hello everyone,

I am facing error while creating GUI in look_up function "Not enough input arguments".

function updateGraph(app, selectedLabel)

gm_id = 0:0.1:50;

id_w = look_up(app.nch, 'ID_W', 'GM_ID', gm_id, 'L', selectedLabel);

% Plot ID_W against GM_ID on the UIAxes component

semilogx(app.UIAxes, (id_w)*10^6, gm_id, 'DisplayName', ['L = ', num2str(selectedLabel)]);

title(app.UIAxes, selectedLabel);

xlabel(app.UIAxes, 'g_m/I_D [S/A]');

ylabel(app.UIAxes, 'I_D/W [A/m]');

end

error:Not enough input arguments.

Error in app1/updateGraph (line 42)

id_w = look_up(app.nch, 'ID_W', 'GM_ID', gm_id, 'L', selectedLabel);

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Answer 1

Jon 2024-4-4，18:40

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https://ww2.mathworks.cn/matlabcentral/answers/2102991-cannot-run-with-provided-input-arguments#answer_1436676

The error is coming from your call to a function named look_up. The error is telling you that you are not supplying this function with enough input arguments. You supply 6, apparently it wants more. Since look_up, is not a standard MATLAB function, it must either be something you wrote, or someone else wrote that you are using. As you don't supply the code for this function I can't give you further details, but you should check the code for your function named look_up, and when you call it be sure to match the list of arguments it is expecting with the ones your are supplying

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Voss 2024-4-4，19:11

在 MATLAB Online 中打开

I don't think the error is from look_up being passed too few arguments; you can always call a function with fewer arguments than are defined in its input argument list. Just calling the function like that doesn't cause an error; an error occurs inside the called function when an input is referred to which has not been passed in.

Example:

fun(1) % error doesn't happen here
       % (it's ok to pass fewer arguments to fun 
       % than it expects - it's up to fun to handle that)
function fun(a,b)
disp([a,b]) % error happens here because b is undefined (fun is not 
            % handling missing arguments properly in this case)
end