how to use a variable in finite field
2 次查看(过去 30 天)
显示 更早的评论
sym a;
I want y=gf(3,8)*a, but it did not work.
回答(2 个)
John D'Errico
2024-4-6
编辑:John D'Errico
2024-4-6
g = gf(3, 8)
whos g
g is a gf object. But g is not compatible for multiplication by a symbolic parameter. These are two independent (and unfortunately, incompatible) toolboxes. They don't talk to or with each other. This is why when you do try to multiply g with a symbolic object, it fails.
syms a
g*a
As the error message says, the only things you can multiply a gf object by are in that list of numeric classes. A sym is not one of the allowed classes for that operation.
You could possibly write your own set of tools that would work as you wish, essentially rewriting the gf class. Since a sym can take on any value, and it MUST be discrete for that operation to make any sense at all, it might take some work on your part to do so in a valid way.
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Error Detection and Correction 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!