How to scatter plot
5 次查看(过去 30 天)
显示 更早的评论
hi guys, im trying to plot my X,Z coordinate to a scatter plot. My problem is shown in figure below:
It is becuase my X is a 1x16 double and my Z is a 1x32 double. When i do [X1,X2], it just reads X1 because X1 and X2 has same value in each variable.
Here are my code :
clear;
clc;
H = 5;
L = 15;
Ns = 2;
Nb = 1;
PortalHeight = H;
Bayspan = L;
NumberStory = Ns;
NumberBay = Nb;
%Variable1
h = [0.8,1.00,1.20,1.40,1.6,1.80];
%Variable2
Lss = [2.00,2.40,2.80,3.20,3.60,4.00]
%Variable3
Nss = [2,3,4];
Var1HeightTrussBeam = h;
Var2LengthSpecialSegment = Lss;
Var3NumberSpecialSegment = Nss;
%% XZ Column
for i = 1:NumberBay+1
Xcolumn(i)=L*(i-1);
Xbotbeam(i)=L*(i-1);
end
for j = 1:NumberStory+1
Zcolumn(j) = H*(j-1);
Zbotbeam(j)=(H*(j-1)-h(1));
end
Zbotbeam = Zbotbeam(1,[Ns,Ns+1]);
%calculate segment length of ordinary segment
Los = (L-Lss(1))/2;
Nos = Los/h(1);
Nos = round(Nos);
los = Los/Nos;
checkspan = logical(los*Nos*2+Lss(1)==15)
assert(logical(los*Nos*2+Lss(1)==15),"span must be 15m");
%% 1st Story
%XZ first top and bottom ordinary segment(os)
XTopOrdinarySegment = repmat(0,1,(NumberBay)*Nos);
ZTopOrdinarySegment = repmat(0,1,(NumberStory)*Nos);
XBottomOrdinarySegment = XTopOrdinarySegment;
ii = 0;
jj = 0;
for i = 1:NumberBay
for k = 1:Nos
ii = ii+1;
XTopOrdinarySegment(ii) = los*k*i;
XBottomOrdinarySegment(ii) = los*k*i;
end
end
for j = 1:NumberStory
for k = 1:Nos
jj = jj+1;
ZTopOrdinarySegment(jj) = H*(j);
ZBottomOrdinarySegment(jj) = (H*(j)-h(1));
end
end
X = [XTopOrdinarySegment,XBottomOrdinarySegment]
Z = [ZTopOrdinarySegment,ZBottomOrdinarySegment]
scatter(X,Z,'filled'),grid on
0 个评论
采纳的回答
Voss
2024-4-10
编辑:Voss
2024-4-10
"It is because my X is a 1x16 double and my Z is a 1x32 double."
That's true. That is the problem.
"When i do [X1,X2], it just reads X1 because X1 and X2 has same value in each variable."
No. The problem has nothing to do with X1 and X2 being the same.
The problem is your X are half as long as your Z. That is because Nb=1 and Ns=2.
更多回答(0 个)
另请参阅
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!