Creating matrix from a for loop
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I have this 'for loop' (where A a matrix from my program):
for m=symbols(1:1000)
d1=abs(m-A);
[C,I]=min(d1);
k=A(I);
end
I want from this loop to save the values of 'k' (1000 total) to a (1, 1000) matrix? How can I do this because I am getting some errors!
Thank you...
采纳的回答
Sven
2011-11-13
Hi athpapa,
I don't know what your "A" matrix or "symbols" matrix had, so I will just make them random numbers:
A = randi(500, 10) - 250;
symbols = randi(30,1,1000);
Now, we can make "k" as a vector of numbers (rather than just a single number). Note that I use "i" to iterate from 1:1000 so that we know which element of "k" to save our answer to:
k = zeros(1,1000);
for i = 1:1000
m = symbols(i);
d1=abs(m-A);
[C,I]=min(d1(:));
k(i) = A(I);
end
Does this do what you wanted it to do?
3 个评论
athpapa -
2011-11-13
Sven
2011-11-13
The issue here is *all* about how to store "B", because the way you have it:
B=[00 01 11 10]
will not actually store the "binary bit" aspect - it will just convert it to numbers:
B=[0 1 11 10]
You can try perhaps defining "B" as a cell array of strings:
B={'00' '01' '11' '10'}
In which case I think it will work how you intended:
B([1 3 2 4 1 3])
If this doesn't quite answer you question, it's a good idea to make a new question and post it (since this is off-topic from the original)
Walter Roberson
2011-11-13
dec2bin(A,2) - '0'
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