I have a code in python and want to convert it in matlab format

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def DEM(Km, Gm, Ki, Gi, alphai, phii, phi0=0.0, r=1000, phitol=1.0E-10, gamma=0.01):
phi = np.sum(phii)
fraci = phii / np.sum(phi)
ci = fraci * alphai / r
n = int(np.ceil((np.log(1.0 - phi) - np.log(1.0 - phi0)) / np.sum(np.log(1.0 - ci))))
m = len(alphai)
def func(r):
f = np.empty(m)
f[0] = np.log(alphai[0] / r[0]) + np.log(1.0 - phi0 / phi) - np.log(
1 - ((1.0 - phi) / (1.0 - phi0)) ** (1.0 / n))
for j in range(1, m):
f[j] = f[j - 1] + np.log(alphai[j] / r[j]) + np.log(r[j - 1] / alphai[j - 1] - fraci[j - 1])
return f
def fprime(r):
jac = np.diag(-1.0 / r)
for j in range(0, m - 1):
jac[j + 1:, j] = -1.0 / r[j] + 1.0 / (r[j] - fraci[j] * alphai[j])
return jac
r0 = r * np.ones(m)
ri = fsolve(func, r0, fprime=fprime, factor=0.1)
ci = fraci * alphai / ri
thetai = theta(alphai)
fi = f(alphai, thetai)
K = np.empty(n)
G = np.empty(n)
phi = np.empty(n)
K_ = Km
G_ = Gm
phi_ = phi0
for i in range(n):
dphi = ci[0] * (1.0 - phi_)
K_, G_ = KG(K_, G_, Ki[0], Gi[0], ci[0], thetai[0], fi[0])
phi_ += dphi
for j in range(1, m):
dphi *= ci[j] * (1.0 - ci[j - 1]) / ci[j - 1]
K_, G_ = KG(K_, G_, Ki[j], Gi[j], ci[j], thetai[j], fi[j])
phi_ += dphi
K[i] = K_
G[i] = G_
phi[i] = phi_
return K, G, phi

回答(1 个)

Steven Lord
Steven Lord 2024-4-15
Do you need to convert the code or would being able to run the code in MATLAB be sufficient? If the latter, see the documentation for instructions on how to run Python code in MATLAB.

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