How to make correct Regex?

Question

Nicholas Kavouris 2024-4-19

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2109106-how-to-make-correct-regex

评论： Voss 2024-4-19

I have an output log from a system which i am looking to capture data from. The data is found in the printout in the following phrase:

"actualIntensity: Optional(8.24%)". I would like to capture the 8.24 part of this phrase.

I have been using

regexp(text,'actualIntensity: Optional\(([0-9]*\.[0-9]+)\%)','match')

But this returns the entire phrase.

How can i modify this regex to only return 8.24, without all the other text?

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Dyuman Joshi 2024-4-19

text is a built-in function. Naming variables (or scripts for that matters) using function names is not a good practice in MATLAB.

Best to change the variable name; a standard variable name in this context is txt.

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Answer 1

Voss 2024-4-19

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2109106-how-to-make-correct-regex#answer_1444546

Use 'tokens' instead of 'match'.

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Voss 2024-4-19

在 MATLAB Online 中打开

txt = "actualIntensity: Optional(8.24%)";
% original but with 'tokens'
regexp(txt,'actualIntensity: Optional\(([0-9]*\.[0-9]+)\%)','tokens')
ans = 1x1 cell array
    {["8.24"]}
% original but with 'tokens','once'
regexp(txt,'actualIntensity: Optional\(([0-9]*\.[0-9]+)\%)','tokens','once')
ans = "8.24"
% removing \ before % and combining the [0-9]
regexp(txt,'actualIntensity: Optional\(([0-9\.]+)%)','tokens','once')
ans = "8.24"
% capturing anything between ( and %) in the input string
regexp(txt,'actualIntensity: Optional\((.*)%)','tokens','once')
ans = "8.24"