Help with updating for loop
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Hi all,I have a problem with the following sample code:
M=[1 2 3 4 5 6 7 8 9 10] for i=1:length(M) M(i)=[] end
My code is not complete, but my problem is that when one row is omitted from the matrix, the size reduces to 9, so the code gets stock with an error to find M(10). Actually, I want to update the cell size in for loop. In my code, I must make some rows empty, I can not keep them. Thanks
采纳的回答
You can iterate backwards, so that subsequent indexing is never off the end of M.
Example:
M=[1 2 3 4 5 6 7 8 9 10];
for i=length(M):-1:1
M(i)=[];
end
M
Or you can store the indices to delete, and delete them all after the loop.
Example, using numeric indices:
M=[1 2 3 4 5 6 7 8 9 10];
to_delete = [];
for i=1:length(M)
to_delete(end+1) = i;
end
M(to_delete)=[];
M
Example, using logical indices:
M=[1 2 3 4 5 6 7 8 9 10];
to_delete = false(1,numel(M));
for i=1:length(M)
to_delete(i) = true;
end
M(to_delete)=[];
M
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