How to make a graph (or part of a graph) of space from a given equation or inequality

Question

根红 2024-4-25

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2111501-how-to-make-a-graph-or-part-of-a-graph-of-space-from-a-given-equation-or-inequality

编辑： Torsten 2024-5-5

在 MATLAB Online 中打开

题目：绘制球体x^2+y^2+z^2<=16与圆柱面x^2+y^2=4x所截的空间立体图形。

我的代码是：

%绘制球面

Question: Draw the spatial three-dimensional figure intercepted by the sphere x^2+y^2+z^2<=16 and the cylindrical surface x^2+y^2=4x.

My code is:

%Draw the sphere

phi=0:0.1:pi;

theta=-pi:0.1:pi;

[phi,theta]=meshgrid(phi,theta);

x1=4.*sin(phi).*cos(theta);

y1=4.*sin(phi).*sin(theta);

z1=4.*cos(phi);

surf(x1,y1,z1)

hold on

%绘制柱面

s=-5:0.1:5;

t=-pi:0.1:pi;

[s,t]=meshgrid(s,t);

x2=2+2*cos(t);

y2=2*sin(t);

z2=s;

surf(x2,y2,z2)

运行结果显示是两个空间曲面相交而成的图形。

我的问题：如何绘出在第一卦限部分的立体？

尝试：我通过更改参数的范围好像不能达到理想的图形。

The running result shows a graph formed by the intersection of two spatial surfaces.

My question: How to draw the solid in the first hexagram?

Try: I can't seem to achieve the ideal graph by changing the range of parameters.

3 个评论
显示 1更早的评论隐藏 1更早的评论

Dyuman Joshi 2024-4-25

You could use alphaShape to get the 3D surface, then use inShape to get the common area and use plot on it.

Though, you will have to adjust the alpha radius.

"我的问题：如何绘出在第一卦限部分的立体"

"My question: How to draw the solid in the first hexagram?"

This is not clear to me. Could you please elaborate on this?

根红 2024-5-5

What I mean is to make a stereoscopic graph in the first octant part; That is, closed stereogram.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

warnerchang 2024-4-26

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2111501-how-to-make-a-graph-or-part-of-a-graph-of-space-from-a-given-equation-or-inequality#answer_1448516

编辑：Walter Roberson 2024-4-26

在 MATLAB Online 中打开

Anything like this:

phi=0:0.1:pi;

theta=0:0.1:pi/2;

[phi,theta]=meshgrid(phi,theta);

x1=4.*sin(phi).*cos(theta);

y1=4.*sin(phi).*sin(theta);

z1=4.*cos(phi);

surf(x1,y1,z1)

hold on

%绘制柱面

s=-5:0.1:5;

t=0:0.1:pi/2;

[s,t]=meshgrid(s,t);

x2=2+2*cos(t);

y2=2*sin(t);

z2=s;

surf(x2,y2,z2)

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Dyuman Joshi 2024-4-27

This does not give the graph of intersecting region.

请先登录，再进行评论。

How to make a graph (or part of a graph) of space from a given equation or inequality

3 个评论
显示 1更早的评论隐藏 1更早的评论

回答（1 个）

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

另请参阅

类别

标签

Community Treasure Hunt

How to make a graph (or part of a graph) of space from a given equation or inequality

3 个评论 显示 1更早的评论隐藏 1更早的评论

回答（1 个）

1 个评论 显示 -1更早的评论隐藏 -1更早的评论

另请参阅

类别

标签

Community Treasure Hunt

3 个评论
显示 1更早的评论隐藏 1更早的评论

1 个评论
显示 -1更早的评论隐藏 -1更早的评论