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how to form rectangular matrix of x, y, z in (:,:,3) format from circular data

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Dhelp
Dhelp 2015-4-20
关闭： MATLAB Answer Bot 2021-8-20
I have data of D(:,:,3) format where x= 5*sin(theta)cos(phi), y=5*sin(theta)sin(phi) and z some data related to this points where theta= 0-pi/2 and phi = 0-2 pi. how can i rearrange the data of z in to [X,Y]=ndgrid(x,y) for x=linspace(-t,t,n) , y=linspace(-t,t,n) format?
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Dhelp
Dhelp 2015-4-21
let phi = 0, theta = 0:pi/100:2*pi, so we have a matrix (1,100) so for each phi until pi/2 , lets say we have (100,100) matrix , and since x, y, z have different formula we have D(100,100, 3) but this data is not sorted in x or y incremental way , so what i need is to make the matrix in an incremental grid format lets say X=[-5:5], Y=[-5 5]
Titus Edelhofer
Titus Edelhofer 2015-4-21
Hi,
please take a look at the answer below: if you have e.g. x=-5:0.5:5, y=-5:0.5:5, then create matrices X, Y with
[X,Y] = meshgrid(x,y);
Use these matrices as points xi, yi when calling griddata.
Titus

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Titus Edelhofer
Titus Edelhofer 2015-4-21
Hi,
if I understand correctly you have a set of points which are given on 3D spheres and want to have them on a regular (cartesian) grid. If this is the case, then you are looking for the function
griddata
You construct the grid using meshgrid or ndgrid and use griddata to interpolate your points onto this grid.
Titus

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