Appending data when extracting nested fields as individual variables
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Hi Matlab community,
I have a variable "hands" that contains several fields, and I am trying to make hand_type, one of the fields, as an individual variable. The size of "hands" varies between 1x1 struct and 1x2 struct, hence I used the if-elseif loop. When "hands" is 1x2 struct, I want the second group of data to be stored in a parallel cell next to the first group of data, hence the {end+1}, as I don't want them to be in the same cell and create an additional layer of nesting.
However, in the resulting "hand_type", whenever "hands" is 1x2 struct, "hand_type" only has 0x0 double. In comparison, when "hands" is 1x1 struct, "hand_type" has a value of a number (0, 1, etc).
Could someone help me to identify what I am doing wrong, and how I can fix the problem? The full script is attached.
Thank you in advance!
has_hands = ~cellfun(@isempty, {frames.hands});
filtered_frames = frames(has_hands);
id = {filtered_frames.id};
time = {filtered_frames.timestamp};
hands = {filtered_frames.hands};
hand_type = cell(size(hands));
for i = 1:numel(hands)
if isequal(size(hands{i}),[1,1])
hand_type{i} = hands{i}.type;
elseif isequal(size(hands{i}),[1,2])
hand_type{end+1} = hands{i}(1).type;
hand_type{end+1} = hands{i}(2).type;
end
4 个评论
Voss
2024-4-30
@Julia Thanks for that!
However, it looks like the variable in the .mat file is not similar to what you describe in the question.
S = load('frames.mat')
frames = S.first100
temp = [frames.frames]
any(temp)
It is a struct array with one field (called "frames") containing all scalar zeros, instead of a struct array with multiple fields ("hands", "id", "timestamp").
采纳的回答
Stephen23
2024-5-1
编辑:Stephen23
2024-5-1
The simple and efficient MATLAB approach using two comma-separated lists (no loops are required!):
first100 = load('frames.mat').first100
tmp = [first100.hands]; % 1x140 structure array
hand_type = [tmp.type] % 1x140 double array
7 个评论
Stephen23
2024-5-1
"For my new variable "thumb_1", I would need all data of "prev_joint" in row 1 for each "bones" structure. However, I am having troubles accessing that."
In total there are 2700 BONES structures: perhaps you only want to access a subset of them.
"Row 1" is confusing me... I do not see any arrays which have more than one row.
first100 = load('frames.mat').first100
tmp = [first100.hands]
digits = [tmp.digits]
id0 = [digits.finger_id]==0;
nnz(id0)
bones = [digits.bones]
[bones.prev_joint]
Perhaps something like this:
thumb = [digits(id0).bones]
or perhaps this, which returns the first element of each structure array:
first = cellfun(@(s)s(1),{digits(id0).bones})
[first.prev_joint]
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SAI SRUJAN
2024-5-1
编辑:SAI SRUJAN
2024-5-1
Hi Julia,
I understand that you are facing an issue appending data when extracting nested fields as inidividual variables.
Please go through the following code sample to proceed further,
has_hands = ~cellfun(@isempty, {first100.hands});
filtered_first100 = first100(has_hands);
id = {filtered_first100.id};
time = {filtered_first100.timestamp};
hands = {filtered_first100.hands};
hand_type = {};
for i = 1:numel(hands)
if isequal(size(hands{i}), [1,1])
hand_type{end+1} = hands{i}.type;
elseif isequal(size(hands{i}), [1,2])
hand_type{end+1} = hands{i}(1).type;
hand_type{end+1} = hands{i}(2).type;
end
end
The variable 'hands' is a 1x99 struct, containing 41 structs within it, each of size [1,2]. Therefore, the expected size of 'hand_types' should be 140 double as we are parallelly storing the values instead of nesting.
I hope this helps!
2 个评论
Stephen23
2024-5-1
编辑:Stephen23
2024-5-1
"The variable 'hands' is a 1x99 struct"
No, it is actually a cell array (not a structure). Lets check it right now (note that MATLAB tells us it is a cell array too):
first100 = load('frames.mat').first100;
has_hands = ~cellfun(@isempty, {first100.hands});
filtered_first100 = first100(has_hands);
hands = {filtered_first100.hands} % <- here you define HANDS as a cell array.
isstruct(hands) % is it a struct array? (hint: no)
iscell(hands) % it is a cell array (exactly as I wrote)
If you had used square brackets it would be a structure array (and more efficient data design).
"containing 41 structs within it, each of size [1,2]."
Lets now check that misinformation as well:
C = cellfun(@size,hands,'uni',0);
unique(vertcat(C{:}),'rows')
Some of the structures are scalar (i.e. 1x1), some have size 1x2 (just as the OP correctly stated).
"Therefore, the expected size of 'hand_types' should be 140 double as we are parallelly storing the values instead of nesting."
But it won't be, because you defined it to be a cell array, not a double array (you can confirm this by actually running your code):
hand_type = {}; % <- cell array
Note that storing lots of scalar numerics in a cell array is very inefficient data design and should be avoided.
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