Error with matrix calculation
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% matrix calculation
M3 = [0 0 0 0 -1 0 0 0 0 0 1 0;
0 0 0 0 0 1 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 -0.05 1;
1 0 0 0 0 0 0 0 -1 0 -1 0;
0 -1 0 0 0 0 0 0 0 -1 0 0;
-0.15 0 0 0 0 0 0 0 -0.15 0 0.05 0;
-1 0 1 0 0 0 0 0 0 0 0 0;
0 1 0 1 0 0 0 0 0 0 0 0;
-0.4*sind(20) -0.4*cosd(20) -0.4*sind(20) 0.4*cosd(20) 0 0 0 0 0 0 0 0;
0 0 0 -1 0 0 0 1 0 0 0 0;
0 0 (BD/2)*cosd(Angle_FBD) (BD/2)*sind(Angle_FBD) 0 0 (BD/2)*cosd(Angle_FBD) (BD/2)*sind(Angle_FBD) 0 0 0 0];
N3 = [mass_body1*Acceleration_G1x;
mass_body1*Acceleration_G1y+mass_body1*9.81;
mass_body1*radius_body1^2*alpha_1;
mass_body2*Acceleration_G2x;
mass_body2*Acceleration_G2y+mass_body2*9.81;
(1/12)*mass_body2*radius_body2^2*alpha_2;
mass_body3*Acceleration_G3x;
mass_body3*Acceleration_G3y+mass_body3*9.81;
(1/12)*mass_body3*radius_body3^2*alpha_3;
mass_body4*Acceleration_G4x;
mass_body4*Acceleration_G4y+mass_body4*9.81;
(1/12)*mass_body4*BD^2*alpha_4];
X = M3/N3
It says that there is an error using "/" and that matrix dimensions must agree. I dont know exactly what this means, and can't find where the issue is. The error is in the line "X = M3/N3"
4 个评论
Steven Lord
2024-5-2
What are the sizes of M3 and N3 immediately prior to executing that line of code? Insert these commands on the lines before the one where the error is thrown and show us what they display.
size(M3)
size(N3)
Tobias
2024-5-3
Tobias
2024-5-3
Tobias
2024-5-3
回答（2 个）
James Tursa
2024-5-2
We don't have all the variables necessary to run your code, but guessing that maybe you need element-wise divide instead of matrix divide?
X = M3 ./ N3
Note the period, so try ./ instead of just /
When you use the / (matrix right divide) operator, the two operands must have the same number of columns. The resulting matrix will have a size that is the number of rows of the first operand, by the number of rows of the second operand.
A = rand(5,3); B = rand(7,3);
A / B
You appear to be constructing an 11 x 12 matrix and dividing it by a 12 x 1 matrix. None of the operators \ .\ / or ./ would be suitable for that purpose.
It would not be an error to calculate
X = M3/N3'
which would then be an 11 x 12 matrix divided by a 1 x 12 matrix, which would give an 11 x 1 result.
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