Matrix does not want to multiply and gives an error when I multiply a 3x3 matrix with a 3x1 matrix

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Gihahn
Gihahn 2024-5-8
回答： Stephen23 2024-5-16
Ran in:
A=[9,29.3, 140.99; 29.3, 140.99,827.693; 140.99, 827.693, 5400.863]
A = 3x3
1.0e+03 * 0.0090 0.0293 0.1410 0.0293 0.1410 0.8277 0.1410 0.8277 5.4009
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Ainv=inv(A); % inverse matrix
B=[4.6;-16; -267.29] % B matrix used in A^-1*B
B = 3x1
4.6000 -16.0000 -267.2900
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values = B * Ainv %multiply the matrix to get a and b
Error using *
Incorrect dimensions for matrix multiplication. Check that the number of columns in the first matrix matches the number of rows in the second matrix. To operate on each element of the matrix individually, use TIMES (.*) for elementwise multiplication.
the multiplication does not want to multiply
  1 个评论
Steven Lord
Steven Lord 2024-5-16
Ran in:
There's no need to call inv here and multiply. Yes, I know that's probably what you were taught in school, but to use A to solve a system of equations A*x = b compute x = A\b instead.
format longg
A=[9,29.3, 140.99; 29.3, 140.99,827.693; 140.99, 827.693, 5400.863]
A = 3x3
1.0e+00 * 9 29.3 140.99 29.3 140.99 827.693 140.99 827.693 5400.863
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B=[4.6;-16; -267.29]
B = 3x1
4.6 -16 -267.29
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values = A\B
values = 3x1
-1.76108777348174 2.72268694776457 -0.420774080489157
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checkThatAxEqualsB = A*values-B % Should contain values very close to 0
checkThatAxEqualsB = 3x1
1.0e+00 * 8.88178419700125e-15 5.6843418860808e-14 5.6843418860808e-14
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回答（4 个）

Voss
Voss 2024-5-8
Ran in:
Do Ainv*B not B*Ainv
A=[9,29.3, 140.99; 29.3, 140.99,827.693; 140.99, 827.693, 5400.863]
A = 3x3
1.0e+03 * 0.0090 0.0293 0.1410 0.0293 0.1410 0.8277 0.1410 0.8277 5.4009
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Ainv=inv(A) % inverse matrix
Ainv = 3x3
0.8808 -0.4791 0.0504 -0.4791 0.3313 -0.0383 0.0504 -0.0383 0.0047
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B=[4.6;-16; -267.29] % B matrix used in A^-1*B
B = 3x1
4.6000 -16.0000 -267.2900
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values = Ainv*B %multiply the matrix to get a and b
values = 3x1
-1.7611 2.7227 -0.4208
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sai charan sampara
编辑：sai charan sampara 2024-5-8
Ran in:
Hello Gihahn,
In line 2 "mat1" is not defined. If you want to have the inverse of "A" replace it with A. Also the size of "B" is 3x1 and "A" is 3x3 matrix. So trying to multiply "B" with "A" will give an error. You can take the transpose of "B" and then multiply with "A" or change the order of multiplication for the dimensions to agree for multiplication.
A=[9,29.3, 140.99; 29.3, 140.99,827.693; 140.99, 827.693, 5400.863]
A = 3x3
1.0e+03 * 0.0090 0.0293 0.1410 0.0293 0.1410 0.8277 0.1410 0.8277 5.4009
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
Ainv=inv(A); % inverse matrix
B=[4.6;-16; -267.29] % B matrix used in A^-1*B
B = 3x1
4.6000 -16.0000 -267.2900
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values = B' * Ainv
values = 1x3
-1.7611 2.7227 -0.4208
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values = Ainv*B
values = 3x1
-1.7611 2.7227 -0.4208
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Ahmed Abed
Ahmed Abed 2024-5-16
You are multiplying [3x1] matrix by [3x3] one, which is mathmatically incorrect.
If you try values = Ainv*B then you will get an answer (not sure if it is what you wanting).
Stephen23
Stephen23 2024-5-16
Ran in:
Read the INV documentation! And then use the recommended function MLDIVIDE:
A = [9, 29.3, 140.99; 29.3, 140.99,827.693; 140.99, 827.693, 5400.863];
B = [4.6; -16; -267.29]
B = 3x1
4.6000 -16.0000 -267.2900
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C = A\B
C = 3x1
-1.7611 2.7227 -0.4208
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