How plot a grid of rectangles on an overlaid circle?
11 次查看(过去 30 天)
显示 更早的评论
How to plot a circle of radius R and an overlaid grid of rectangles (with each rectangle of dimensions LxW)?
Choice of dimensions are so that the rectangular grid is larger than the dimeter of the circle and the centre of the circle is on one of the rectangle corners within the grid. The circle fully sits within the rectangular grid.
Secondly, from the plot or otherwise can Matlab help count the full rectangles within the circle?
0 个评论
采纳的回答
Matt J
2024-5-20
编辑:Matt J
2024-5-20
R = 5; % circle radius
H = 1; % rect height
W = 2; % rect width
circ=nsidedpoly(1000,"Radius",R); %polyshape for the circle
Grid=scale(nsidedpoly(4,'Side',1,'Center',[+1,+1]/2),[W,H]);
Grid=arrayfun(@(i)translate(Grid,H*[0,i]),-ceil(R/H):ceil(R/H)-1)';
Grid=arrayfun(@(i)translate(Grid,W*[i,0]),-ceil(R/W):ceil(R/W)-1,'uni',0);
Grid=vertcat(Grid{:}); %polyshape vector for grid rectangles
numContained=sum( area(intersect(Grid,circ))>=area(Grid(1))*0.9999 ) %count contained rectangles
plot([circ; Grid],'FaceColor','w'); axis equal
13 个评论
更多回答(1 个)
Voss
2024-5-20
R = 5; % circle radius
L = 1; % horizontal grid spacing
W = 2; % vertical grid spacing
C = [7 8]; % center of the circle
% calculate some points on the circle
th = linspace(0,2*pi,100);
xc = C(1)+R*cos(th);
yc = C(2)+R*sin(th);
% calculate the grid's x and y coordinates
xg = C(1)+W*(floor(-R/W):ceil(R/W));
yg = C(2)+L*(floor(-R/L):ceil(R/L));
% plot the circle
plot(xc,yc)
axis equal
% create the vertical grid lines
nx = numel(xg);
xdata = [xg;xg;NaN(1,nx)];
ydata = [repmat(yg([1 end]).',1,nx); NaN(1,nx)];
line(xdata,ydata,'Color','k')
% create the horizontal grid lines
ny = numel(yg);
ydata = [yg;yg;NaN(1,ny)];
xdata = [repmat(xg([1 end]).',1,ny); NaN(1,ny)];
line(xdata,ydata,'Color','k')
% count the rectangles completely inside the circle
n_rectangles_inside = nnz(conv2((xg-C(1)).^2+(yg.'-C(2)).^2 <= R^2,ones(2)) == 4)
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Data Exploration 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!