Force symbolic simplification to eliminate variable

2 次查看(过去 30 天)
When breaking down a (long and complex) formula into the form , I use the approach of the lincoeffs script.
The problem is, that I still have u in b, because simplification isn't detecting that the terms cancel out.
Is there a trick to force the elimination of u-terms?
The symbolic expression is attached if you want to try it, the code is as follows:
% NOT WORKING - extract coefficients of ddddh_fun
syms u
% ddddh_fun = expand(ddddh_fun);
ddddh_fun_formula = formula(ddddh_fun) == 0;
[ddddh_fun_A,ddddh_fun_b] = lincoeffs(ddddh_fun_formula,u)
ddddh_fun_b = simplify(ddddh_fun_b,'Steps',50);
---
% WORKING - extract coefficients of ddddh_fun
syms u
ddddh_fun = expand(ddddh_fun);
ddddh_fun_formula = formula(ddddh_fun) == 0;
[ddddh_fun_A,ddddh_fun_b] = lincoeffs(ddddh_fun_formula,u)
ddddh_fun_b = simplify(ddddh_fun_b,'Steps',50);
The problem with this is, that the very expanded expression from the working version isn't very readable when I do export is as Latex, which is necessary for me.
To read the symbolic function and the matlabFunction derived from this is also very hard this way.

采纳的回答

Paul
Paul 2024-5-24
Hi ludolfusexe,
load ddddh_fun
symvar(ddddh_fun)
ans = 
syms u
% A*u = b
[A,b] = equationsToMatrix(ddddh_fun == 0,u)
A = 
b = 
Verify that A and b do not depend on u
symvar(A)
ans = 
symvar(b)
ans = 
Reverse sign of b for desired form: A*u + b = 0
b = -b;
Verify
simplify(ddddh_fun - (A*u + b))
ans(t) = 
0

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