How to make Matlab recognize that an expression rewritten by using subexpr() is equal to the original expression?

4 次查看（过去 30 天）
Elif Cansu
Elif Cansu 2024-5-26
编辑： Torsten 2024-5-26
Ran in:
I would expect the isAlways() function below to return 1 but for some reason Matlab does not recognize that x=x_2. Is there a way to solve this problem?
syms a b c d e f x
x = a + (a+b+c+d+e)^(1/2) + c*(e+f+(a+b+c+d+e)^(1/2));
x_2 = subexpr(x)
sigma =
x_2 = 
isAlways(x_2==x)
Warning: Unable to prove 'a + sigma + c*(e + f + sigma) == a + c*(e + f + (a + b + c + d + e)^(1/2)) + (a + b + c + d + e)^(1/2)'.
ans = logical
0

请先登录，再回答此问题。

回答（1 个）

Torsten
Torsten 2024-5-26
编辑：Torsten 2024-5-26
Ran in:
You have to resubstitute sigma by (a+b+c+d+e)^(1/2) in x_2 to compare with x:
syms a b c d e f x
x = a + (a+b+c+d+e)^(1/2) + c*(e+f+(a+b+c+d+e)^(1/2));
x_2 = subexpr(x)
sigma =
x_2 = 
isAlways(subs(x_2)==x)
ans = logical
1

类别

在 Help Center 和 File Exchange 中查找有关 Assumptions 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by