how to use an integral function inside a for loop? i need to find the value of function that chages as i chages .then using this values i need to find another integral.

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Aparna Sekhar 2024-6-5

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https://ww2.mathworks.cn/matlabcentral/answers/2125561-how-to-use-an-integral-function-inside-a-for-loop-i-need-to-find-the-value-of-function-that-chages

评论： Aparna Sekhar 2024-6-6

r0 =0.1

u =[1:7]'

Q =zeros(length(u),1)

E =zeros(length(Q),1)

for i =1:length(u)

Q(i,1) =0.023*(r0^(-1/4))*((u(i))^(-14/4))

f =@(Q) (Q(i)).^(0.3)

E(i,1) =integral(f,1,7)

end

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Aparna Sekhar 2024-6-5

Hi Thank you for your respone.Im new to matlab so there may be many mistakes

Q(u)=0.023*r0^(-1/4)*u^(-14/4)

E(u1)= integral from u0 to u2 [Q(u)^(0.3)]du

where u is a range of numbers

u1 is between u0 and u2

Torsten 2024-6-5

E(u1)= integral from u0 to u2 [Q(u)^(0.3)]du

You define E as a function of u1, but u1 does not appear on the right-hand side.

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回答（1 个）

Alan Stevens 2024-6-5

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https://ww2.mathworks.cn/matlabcentral/answers/2125561-how-to-use-an-integral-function-inside-a-for-loop-i-need-to-find-the-value-of-function-that-chages#answer_1467806

在 MATLAB Online 中打开

Are you looking for something like this?

r0 =0.1;
u =[1:7]';
Q =zeros(length(u),1);
E =zeros(length(Q),1);
Q = @(x)0.023*(r0^(-1/4))*(x.^(-14/4));
f = @(x) Q(x).^0.3;
for i =1:length(u)
    
   u0 = 1; u2 = u(i);
    E(i,1) =integral(f,u0,u2);
    
end
disp(E)
         0
    0.2611
    0.4097
    0.5133
    0.5927
    0.6569
    0.7107