how to use an integral function inside a for loop? i need to find the value of function that chages as i chages .then using this values i need to find another integral.

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Aparna Sekhar
Aparna Sekhar 2024-6-5
评论： Aparna Sekhar 2024-6-6
r0 =0.1
u =[1:7]'
Q =zeros(length(u),1)
E =zeros(length(Q),1)
for i =1:length(u)
Q(i,1) =0.023*(r0^(-1/4))*((u(i))^(-14/4))
f =@(Q) (Q(i)).^(0.3)
E(i,1) =integral(f,1,7)
end
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Aparna Sekhar
Aparna Sekhar 2024-6-5
Hi Thank you for your respone.Im new to matlab so there may be many mistakes
Q(u)=0.023*r0^(-1/4)*u^(-14/4)
E(u1)= integral from u0 to u2 [Q(u)^(0.3)]du
where u is a range of numbers
u1 is between u0 and u2
Torsten
Torsten 2024-6-5
E(u1)= integral from u0 to u2 [Q(u)^(0.3)]du
You define E as a function of u1, but u1 does not appear on the right-hand side.

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回答（1 个）

Alan Stevens
Alan Stevens 2024-6-5
Ran in:
Are you looking for something like this?
r0 =0.1;
u =[1:7]';
Q =zeros(length(u),1);
E =zeros(length(Q),1);
Q = @(x)0.023*(r0^(-1/4))*(x.^(-14/4));
f = @(x) Q(x).^0.3;
for i =1:length(u)
u0 = 1; u2 = u(i);
E(i,1) =integral(f,u0,u2);
end
disp(E)
0 0.2611 0.4097 0.5133 0.5927 0.6569 0.7107

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