Not able to plot a proper graph for the equation.

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y = (1*1*((25)-(x.^2)))/((x.^4)-((x.^2)*((1*(1.78))+(25)+1))+(1*(25)));
fplot(y);
i used this code but am only getting a straight line instead of the 2 peak FRF that I want.
  7 个评论
Kartikeya
Kartikeya 2024-6-8
@Torsten@Sam Chak Is it possible to get a graph like the following one for my case?

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John D'Errico
John D'Errico 2024-6-8
编辑:John D'Errico 2024-6-8
syms x
y = (1*1*((25)-(x.^2)))/((x.^4)-((x.^2)*((1*(1.78))+(25)+1))+(1*(25)))
y = 
First, where are the poles? A pole lives where the denominator is zero.
[N,D] = numden(y)
N = 
D = 
droot = solve(D)
droot = 
double(droot)
ans = 4x1
0.9650 5.1816 -0.9650 -5.1816
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So we need to look between -6 and 6.
fplot(y,[-6,6])
NO. It does not look the way you want it to look. But it is your function. You set the problem. If it does not look like what you want, then maybe you are starting with the wrong function.
  3 个评论
John D'Errico
John D'Errico 2024-6-8
编辑:John D'Errico 2024-6-8
That could be. And you could have offered that as an answer. But my mind reading abilities are sometimes lacking, only answering the question posed, instead of answering a different question. If I always tried that, I'd end up chasing into infinitely many rabbit holes.
Kartikeya
Kartikeya 2024-6-8
@Sam Chak @Torsten @John D'Errico Guys I got the whole thing. Just had to use the absolute values of the y variable that I got. Thanks for your help, all of you.
x = 0:0.1:10;
y = (1*1*((25)-(x.^2)))./((x.^4)-((x.^2)*((1*(1.78))+(25)+1))+(1*(25)));
plot(y);
xlim([0 100]);
ylim([0 inf]);
xlabel('Natural Frequency Ratio');
ylabel('Amplitude x_0');
z = abs(y);
disp(z);
plot(z);

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