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please explain the function of each command used in this code. These commands are part of allan variance code.

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Karishma Chawla
Karishma Chawla 2024-6-16
编辑： DGM 2024-6-17
avar = zeros(numel(m), 1);
for i = 1:numel(m)
mi = m(i);
avar(i,:) = sum((theta(1+2*mi:L) - 2*theta(1+mi:L-mi) + theta(1:L-2*mi)).^2, 1);
end
avar = avar ./ (2*tau.^2 .* (L - 2*m));
adev = sqrt(avar);

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回答（1 个）

DGM
DGM 2024-6-16
  2 个评论
Karishma Chawla
Karishma Chawla 2024-6-16
移动：Voss 2024-6-16
hello, thank you for replying.
can you please let me know how the below command works
avar(i,:) = sum((theta(1+2*mi:L) - 2*theta(1+mi:L-mi) + theta(1:L-2*mi)).^2, 1);
DGM
DGM 2024-6-17
编辑：DGM 2024-6-17
It's the sum of the squares of three segments of the vector theta:
  • a segment at the beginning
  • plus a segment ending at L
  • minus a segment centered between the two
The segments are all of length L-2*m(i), whatever that is.

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