Creating a 3-dim matrix from an array and a 2-dim matrices array

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I am trying to create a 3-dimensional matrix (e.g. 80 x 300 x 350) from an array (dim 80) and an array of 80 300 x 350 matrices. The second dimension in matrices may vary, so it needs to be padded by 0.

Any hint is welcome.

I have tried this:

for i=1:80
res(i,:,:)=cell2mat(s1(i));
end

and got this:

Subscripted assignment dimension mismatch.

Thank you

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James Tursa 2015-4-22

If you are using the 300 x 350 slices downstream in your code, you might consider making those the first two dimensions of your 3D matrix so the slices are contiguous in memory. E.g., a 300 x 350 x 80 array.

Valentina Baljak 2015-4-22

thanks for the hint, James, might be useful in the future

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Answer 1

Sean de Wolski 2015-4-22

在 MATLAB Online 中打开

0 个投票

Close! but using :,: means that it must fill the whole thing, not pad with zeros. Instead, only fill to the size:

for i=1:80
  sii = cell2mat(s1(i));
  res(i,1:size(sii,1),1:size(sii,2)) = permute(sii,[3 1 2]); % permute to write orientation
end

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Valentina Baljak 2015-4-22

Thank you, that looks like shorter solution. In a meanwhile, I have tried more direct approach, using the coder logic, I guess.

%zero 3D matrix, placeholder predict=zeros(80, 300, 350);

for i=1:80 temp=cell2mat(s1(i)); dims=size(temp); d=dims(2); for j=1:300 for k=1:d predict(i,j,k)=temp(j,k); end end end

and it works well enough.

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