Creating a 3-dim matrix from an array and a 2-dim matrices array

12 次查看（过去 30 天）
Valentina Baljak
Valentina Baljak 2015-4-22
评论： Valentina Baljak 2015-4-22
I am trying to create a 3-dimensional matrix (e.g. 80 x 300 x 350) from an array (dim 80) and an array of 80 300 x 350 matrices. The second dimension in matrices may vary, so it needs to be padded by 0.
Any hint is welcome.
I have tried this:
for i=1:80
res(i,:,:)=cell2mat(s1(i));
end
and got this:
Subscripted assignment dimension mismatch.
Thank you
  2 个评论
James Tursa
James Tursa 2015-4-22
If you are using the 300 x 350 slices downstream in your code, you might consider making those the first two dimensions of your 3D matrix so the slices are contiguous in memory. E.g., a 300 x 350 x 80 array.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Sean de Wolski
Sean de Wolski 2015-4-22
Close! but using :,: means that it must fill the whole thing, not pad with zeros. Instead, only fill to the size:
for i=1:80
sii = cell2mat(s1(i));
res(i,1:size(sii,1),1:size(sii,2)) = permute(sii,[3 1 2]); % permute to write orientation
end
  1 个评论
Valentina Baljak
Valentina Baljak 2015-4-22
Thank you, that looks like shorter solution. In a meanwhile, I have tried more direct approach, using the coder logic, I guess.
%zero 3D matrix, placeholder predict=zeros(80, 300, 350);
for i=1:80 temp=cell2mat(s1(i)); dims=size(temp); d=dims(2); for j=1:300 for k=1:d predict(i,j,k)=temp(j,k); end end end
and it works well enough.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by