Prooving a trained LSTM regression model

4 次查看（过去 30 天）
James
James 2024-7-3
回答： Ayush Aniket 2024-7-8
Hello
I am interested in proving how to derive the output given a new input value through the trained LSTM model.
I already know how to predict with new input data such as :
output = model.predict(input);
or
output = predict(model, input);
However, I am interested in a formula that uses the optimized variables of the trained LSTM (the variables shown in the figure below) to derive the results.
If you know what kind of calculation formula the output is derived when a new input value is given in LSTM, please help me.

请先登录，再回答此问题。

采纳的回答

Ayush Aniket
Ayush Aniket 2024-7-8
Hi James,
To find the output using the weights of your trained layers, you will have to implement the equations for all the layers in your model. For the LSTM layer, refer this document section which shows the equations used to compute the output for each time step:
https://www.mathworks.com/help/deeplearning/ref/nnet.cnn.layer.lstmlayer.html#mw_9f7c5f93-4bf2-4ddb-b922-b1c122668b9a_sep_mw_8cad7fee-7610-4134-9354-b7ed3a45204d_head
You would have to repeat the process for all the Fully Connected layers as well keeping in mind the size of input for the respective layers. Refer the following documentation section which provides the respective formulae:
https://www.mathworks.com/help/deeplearning/ref/nnet.cnn.layer.fullyconnectedlayer.html#mw_5c678e5e-5bd0-491b-9272-b6b72f65e417_head
Note: You will also have to take care of the pre and post processing functions that MATLAB layers implicitly apply to better train the neural network. The following MATLAB answer can guide you: https://www.mathworks.com/matlabcentral/answers/2068661-using-the-trained-lstm-weight-parameters-in-matlab-the-results-obtained-by-calculating-with-a-formu

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Sequence and Numeric Feature Data Workflows 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by