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index no for iterations

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Nitheesh M
Nitheesh M 2015-4-25
回答： Stephen23 2015-4-25
Attempted to access x(2,1.01); index must be a positive integer or logical.
Error in ==> latest at 19 dx1=x(2,i);
my code ::
for i = 0:0.01:2 yd(j) = sin(2*pi*i); j=j+1; dx1=x(2,i);
should i be integer values only..if then my yd will always be 0 right..i need values of yd from 0 to 2..and corresponding dx1...
please help me out

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Stephen23
Stephen23 2015-4-25
You probably don't need a loop at all, and can simply vectorize the code anyway:
x = 0:0.01:2;
y = sin(2*pi*x);
and most likely any following value manipulations can also be vectorized. This is much faster and neater than using loops, which as something low-level programming languages rely on but are not a good use of MATLAB.

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