Discrete time nonlinear system

5 次查看(过去 30 天)
How can i develop this discrete-time nonlinear system in simulink?
[x]=[0.01x1 - x2; x1 - 0.003x2^2]

采纳的回答

Fangjun Jiang
Fangjun Jiang 2011-11-16
Grab an Integrator block, if the input is dx1/dt, then the output is x1. Do the same for x2 and then you have all you need to build the equation. x2^2 is the same as x2*x2.
You don't seem to have any inputs, so set the initial condition of the Integrator blocks to specify the initial value of x1 and x2 and then run the simulation to see the dynamics.
  4 个评论
dab483
dab483 2011-11-17
sorry.it is my mistakes. i type it wrongly. it suppose
x1(k+1)=0.01*x1(k)-x2(k);
x2(k+1)=x1(k)-0.003*x2^2(k);
Fangjun Jiang
Fangjun Jiang 2011-11-17
Then replace the Integrator block with the Unit Delay (1/Z) block. The input is x(k+1), the output is x(k).

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 General Applications 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by