to conrert a complex decimal value into a binary form

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DSP Masters
DSP Masters 2011-11-16
评论： Inzamamul Haq 2018-9-29
Hi, Please Help me in converting a complex decimal value into its equivalent 32 bit binary value where, first 16 bits represents the real part of the complex value and second 16 bits represents imaginary part of the complex value.. For example: If the value is "0.5 + 0.5i"
I need to get 32 bit => "01000000000000000100000000000000"
Here both real and imaginary part has to be converted to signed q15

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回答（1 个）

Walter Roberson
Walter Roberson 2011-11-16
t = real(x);
u = imag(x);
num = uint32(((t<0) + abs(t)) * 2^15) * 2^16 + uint32(((u<0) + abs(u)) * 2^15);
Unless, that is, you really need the bit vector itself:
bits = [+(t<0), dec2bin(fix(abs(t) * 2^15),15)-'0', +(u<0), dec2bin(fix(abs(u) * 2^15)-'0'];
  1 个评论
Inzamamul Haq
Inzamamul Haq 2018-9-29
hello sir,I used this method its working..now i'm having an another doubt from this out put how to re convert the complex number

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