i have a vector in lenght 5, i need to check if a sum of 2 or more elements in the vector is equal to another element at the same vector how to do that?

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omer 2024-7-16，13:27

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评论： Ayush Aniket 2024-7-17，4:17

i try to do a loop inside a loop but it doesnt works

if someone has an idea it would be helpful.

thank you

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Answer 1

Ayush Aniket 2024-7-16，15:16

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编辑：Ayush Aniket 2024-7-17，3:59

在 MATLAB Online 中打开

Hi Omer,

You can check for the existence of an element which is the sum of two or more elements in the same vector as follows:

Select all combinations of numElements(number of elements) from the vector, where numElements varies from 2 to 5. You can use the nchoosek MATLAB function which returns all the combinations. Refer to the doumentation for the function here: https://www.mathworks.com/help/matlab/ref/nchoosek.html
The next step would be to iterate through the combinations, find the sum and check for the result in the vector. See the code below:

% Iterate over all combinations of 2 or more elements
for numElements = 2:n 
    combs = nchoosek(1:n, numElements); %Find indices of all combinations of size numElements from the vector
    for i = 1:size(combs, 1)
        sumComb = sum(vec(combs(i, :)));
        if any(vec == sumComb)
            result = true;
            return;
        end
    end
end

The result variable returns the answer. The initial value will be false for this variable.

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omer 2024-7-16，19:54

hi, thanks!

just for understandin what does 'n' means?

combs = nchoosek(1:n, numElements)

Ayush Aniket 2024-7-17，4:17

在 MATLAB Online 中打开

Hi Omer, the n refres to the length of the original vector vec i.e.

n = length(vec)

For this problem, the value of n will be 5. In the function nchoosek, we construct and pass the vector 1:5 ([1,2,3,4,5], representing the indices of the original vector) as the vector argument. The function then returns the combination of numElements number of elements from this vector.

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Answer 2

Voss 2024-7-16，15:08

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在 MATLAB Online 中打开

v = [10 5 13 15 28];
m = dec2bin(0:2^numel(v)-1)-'0';
m = m(sum(m,2) >= 2,:);
[ism,idx] = ismember(m*v.',v);
idx = idx(ism);
m = logical(m(ism,:));
for ii = 1:numel(idx)
    disp(join(compose('%g',v(m(ii,:))),'+') + "=" + v(idx(ii)))
end
13+15=28
10+5=15
10+5+13=28