Is there a way to crop an array depending on the values that I want through a function as the values change?

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Simeon
Simeon 2024-7-19
回答： Mathieu NOE 2024-7-19
I currently have a graph that has multiple flat maxima but I only want the index values of the last one. I am currently using islocalmax(data,'flatselection','all') to get all of the local maxima that exist and that then gives me a logical array which I can then either get the index values of all the 1's but I then want the last collection of 1's or the last collection of consecutive indexes. I was just wondering if there was a way to specifically select these values? I could manually find the start point of the last set and then set it to the end but as I want to use it on multiple data sets I want it to be automatic.
peaks = islocalmax(test.CAN_EMTrq,'FlatSelection','all');
peaks1 = find(peaks==1);
This is the code I am using right now.
The table either looks like: 000011111000100001111101111 and I want the last 4 1's or it looks like: 12,13,14,15,34,35,36,37,38,56,57,58,59 and I want the last 4 numbers.
Thanks

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Mathieu NOE
Mathieu NOE 2024-7-19
Ran in:
hello
try this :
a = [0 0 0 0 1 1 1 1 1 0 0 0 1 0 0 0 0 1 1 1 1 1 0 1 1 1 1];
ind = logical(a);
[begin,ends] = find_start_end_group(ind);
duration = ends - begin;
% last group of duration >=3 consecutive samples
ind = duration>=3;
begin = begin(ind);
ends = ends(ind);
% start and end indexes of last buffer of 1's
begin = begin(end)
begin = 24
ends = ends(end)
ends = 27
function [begin,ends] = find_start_end_group(ind)
% This locates the beginning /ending points of data groups
% Important : ind must be a LOGICAL array
D = diff([0;ind(:);0]);
begin = find(D == 1);
ends = find(D == -1) - 1;
end

更多回答（1 个）

Image Analyst
Image Analyst 2024-7-19
Ran in:
The binary option is trivial if you have the Image Processing Toolbox
signal = logical([0,0,0,0,1,1,1,1,1,0,0,0,1,0,0,0,0,1,1,1,1,1,0,1,1,1,1]);
labeledSignal = bwlabel(signal)
labeledSignal = 1x27
0 0 0 0 1 1 1 1 1 0 0 0 2 0 0 0 0 3 3 3 3 3 0 4 4 4 4
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(the display is being truncated and the 4's aren't showing up but they're there) but I don't know exactly what you mean when you say you want the last 4 1's. What does that mean exactly? Do you want to extract a vector of [1 1 1 1] or want their indexes or what????
for the floating point case you need to find out how flat is flat because it's a judgment call. You might want to call some kind of clustering method like dbscan or something. See
https://www.mathworks.com/help/stats/cluster-analysis.html
Machine Learning, classification, clustering
Cluster analysis - Wikipedia, the free encyclopedia
Once you've collected the data into clusters it will be easy to extract the last cluster. See this demo:
v = [12,13,14,15,34,35,36,37,38,56,57,58,59]
v = 1x13
12 13 14 15 34 35 36 37 38 56 57 58 59
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
x = 1 : numel(v);
data = [v; x]'
data = 13x2
12 1 13 2 14 3 15 4 34 5 35 6 36 7 37 8 38 9 56 10
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
scatter(x, v);
result = dbscan(data,5,2)
result = 13x1
1 1 1 1 2 2 2 2 2 3
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<mw-icon class=""></mw-icon>
gscatter(x, v, result); % Visualize the groups it found
% Get last group
indexes = result == max(result)
indexes = 13x1 logical array
0 0 0 0 0 0 0 0 0 1 1 1 1
lastDataGroup = v(indexes)
lastDataGroup = 1x4
56 57 58 59
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<mw-icon class=""></mw-icon>

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