Speed up numeric integral

24 次查看(过去 30 天)
Guan Hao
Guan Hao 2024-7-24
编辑: Guan Hao 2024-7-25
Hi,everyone.I got a problem of doing numeric integral on the matrix H (which is at the bottom part of my code).
The code works fine but I would like to speed it up? Am I doing something stupid to make it slow?Thanks for your help.
clear
L=0.1;
section=50;
a=L./2;
b=L./section;
v=3e8;
f1=1.2e9;
f2=4.8e9;
f3=7.5e9;
f4=10e9;
w1=(2.*pi.*f1);
w2=(2.*pi.*f2);
w3=(2.*pi.*f3);
w4=(2.*pi.*f4);
Z01=50;
Z02=75;
a0=(log(Z02./Z01))./(2..*L);
T=a;
Ub=a;
Lb=-a;
ub=a;
lb=-a;
k=5;
syms x y w m
%%% Revised Algorithm
l=0:(2.*L)./(2.*k):L % Approximate sections dvided
% Approximate terms
sec=numel(l)-1;
Z1=[50 55 60 65 70 80 75]; % Set the impedance of the end of each sections
ac=10; % Choose the accuracy of dividing a section
for s=1:1:sec
c=(l(s+1)-l(s))./ac;
app_cos=0.5./ac.*log(Z1(s+1)./Z1(s)).*sin(ac./2.*(w./v).*c).*cos(((ac+1)./2).*(w./v).*c)./sin(((c.*w)./(2.*v)));
app_sin=0.5./ac.*log(Z1(s+1)./Z1(s)).*sin(ac./2.*(w./v).*c).*sin(((ac+1)./2).*(w./v).*c)./sin(((c.*w)./(2.*v)));
amp=0.75;
Ga(s)=(app_cos-(1i.*amp.*app_sin));
end
Ta=(1-(abs(Ga(1:1:end)).^2));
%%% Turn closed loop terms into matrix presentation
for t=1:1:sec
for r=1:1:sec
E(t,r)=Ga(t).*Ga(r);
end
end
E=triu(E,1);
for t=1:1:sec
for r=1:1:sec
D(t,r)=abs(E(r,t));
end
end
C1=sum(D);
% Construct approximate loop terms
for t=1:1:sec
D1(t)=prod(Ta(1:t))./(1+(sum(C1(1:t))));
end
D=[1 D1(2:end)];
Dm=transpose(D).*D;
% Cmn
m=transpose(1:5);
n=1:5;
g=(v.^2.*w.^2.*cos((2.*w.*(- y + x))./v).*cos(20.*sym(pi).*m.*x).*cos(20.*sym(pi).*n.*y) + 10.*sym(pi).*m.*v.^3.*w.*sin(20.*sym(pi).*m.*x).*sin((2.*w.*(- y + x))./v).*cos(20.*sym(pi).*n.*y) - 10.*sym(pi).*n.*v.^3.*w.*sin(20.*sym(pi).*n.*y).*sin((2.*w.*(- y + x))./v).*cos(20.*sym(pi).*m.*x) + 100.*m.*n.*v.^4.*sym(pi).^2.*sin(20.*sym(pi).*m.*x).*sin(20.*sym(pi).*n.*y).*cos((2.*w.*(- y + x))./v))./(4.*(w.^2 - 100.*sym(pi).^2.*m.^2.*v.^2).*(w.^2 - 100.*sym(pi).^2.*n.^2.*v.^2));
for p=1:numel(l)-1
x1=l(p);
x2=l(p+1);
for q=1:numel(l)-1
y1=l(q);
y2=l(p+1);
Ht{p,q}=matlabFunction(((subs(g,[x y],[x2 y2])-subs(g,[x y],[x1 y1]))*Dm(p,q)));
end
end
Hi=Ht{1};
for m=2:1:numel(Ht)
Hi=Hi+vpa(Ht{m},3);
end
H=integral(Hi,w1,w2,"ArrayValued",true)
  4 个评论
Torsten
Torsten 2024-7-24
编辑:Torsten 2024-7-24
Do you see your mistake ?
syms x y
x1 = 1;
x2 = 2;
y1 = 4;
y2 = 6;
g = 4*x*y;
G = int(int(g,x),y)
G = 
int(int(g,x,x1,x2),y,y1,y2)
ans = 
60
int(int(g,y,y1,y2),x,x1,x2)
ans = 
60
subs(G,[x y],[x2,y2])-subs(G,[x y],[x1,y1])
ans = 
128
Guan Hao
Guan Hao 2024-7-24
编辑:Guan Hao 2024-7-25
@Torsten Oh.Thanks for pointing that out.

请先登录,再进行评论。

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 MATLAB 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by