Converting Equation of Two Variables Into Matrix Elements - ERROR: Invalid MATLAB indexing or symbolic function definition

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Hello everyone,
I am trying to output a square matrix that is N x M in size, where N = M. In my case, N = 3. So this is a "3x3" matrix
I have a variable that's called "Kernel". This variable is calculated as an equation in terms of "z" and "z_prime".
My values in z_prime will vary from L / 2N to (2N-1)*(L/2N) , in steps of "L/N".
My "z" variable will be used as an "integration variable" as seen below.
I am trying to calculate an output called the "Z Matrix" which will integrate the "Kernal" variable across specific ranges.
I attached a .pdf file to clarify my end goal.
See the .pdf file attached:
Z_Matrix_Output.pdf
My Integration Limits for "z" will be going from:
z_start = 0 : L/N : (N-1) * (L/N)
z_end = L/N : L/N : L
As of right now, I'm getting the error:
Invalid MATLAB indexing or symbolic function definition
This is after I tried using "function handles" in my code.
In my attempt, I have tried to use for loops and created function handles to make it easier to generate this matrix.However, I didn't end up with a "N X M" matrix, I just ended up with a "1 X N" matrix.
I know that there is a way to use "nested" for loops to generate a square matrix of an "N X M" size. However, I wasn't quite sure on how to implement that in MATLAB for my case.
I have tried to look through different questions/answers on the Mathworks Forum regarding converting equations of two variables into "matrix elements". However, I wasn't able to find anything that was relevant to my case.
I attached my MATLAB Code for reference.
See MATLAB .m file attached:
Z_Calculation.m

采纳的回答

Shashi Kiran
Shashi Kiran 2024-7-30
Hi Ammar,
The code looks interesting.
I understand that you are encountering errors while using MATLAB's 'integral' function for integration.
According to the documentation, the 'integral' function requires the input argument 'integrand' to be a function handle.
Based on the code and theory you have provided,
The Kernel and function integral can be defined as below.
% Kernel function
Kernel = F_1 * F_2 * (F_3 * F_4 + F_5);
% Convert Kernel to a function handle
Kernel_handle = matlabFunction(Kernel, 'Vars', [z, z_prime]);
% Define the integrand as a function handle
integrand = @(z) Kernel_handle(z, loop_z_prime);
% Integrate using the defined function handle
Z(i,j) = integral(integrand, loop_lower_z, loop_upper_z);
Below is complete implementation of your code using the above arguments
%% Starting Timer and Clearing Plots/Command Line
tic
close all; clc;
%% Fixed Variables and Parameters
% Value of j
j = 1i;
% Speed of light = c = 3*10^8 m/s
c = 3*10^8;
% Frequency = 300 MHz = 300*10^6 Hz = 3*10^8 Hz
f = 3*10^8;
% Value of lambda = c / f
lambda = c/f;
% Wavenumber value = k
k = (2*pi)/lambda;
% Intrinsic Impedance Value = eta
eta = 120*pi;
% Radius of the wire
a = 0.005*lambda;
% Length of the dipole antenna
L = 0.5*lambda;
% Number of segments
N = 3;
% Number of columns
M = N;
% Declaring "z" and "z_prime" as symbolic variables
syms z z_prime;
%% Calculating the Kernel Factor
% R equation
R = sqrt(a^2 + (z - z_prime)^2);
% Factor_1 = (-j*eta) / k
F_1 = (-j*eta) / k;
% Factor_2 = (exp(-j*k*R)) / (4*pi*(R)^5)
F_2 = exp(-j*k*R) / (4*pi*(R)^5);
% Factor_3 = 1 + jkR
F_3 = 1 + (j*k*R);
% Factor_4 = 2*R^2 - 3*a^2
F_4 = (2*R^2) - (3*a^2);
% Factor_5 = (k*a*R)^2
F_5 = (k*a*R)^2;
% Kernel function
Kernel = F_1 * F_2 * (F_3 * F_4 + F_5);
% Convert Kernel to a function handle
Kernel_handle = matlabFunction(Kernel, 'Vars', [z, z_prime]);
% Upper and lower z integration boundaries
delta_z = L / N;
upper_z = 0 : delta_z : L - delta_z;
lower_z = delta_z : delta_z : L;
% Start and stop values for z_prime
z_prime_start = L / (2*N);
delta_z_prime = L / N;
z_prime_end = L - z_prime_start;
z_prime = z_prime_start : delta_z_prime : z_prime_end;
% Pre-allocating the Z Matrix into an N x N Matrix
Z = zeros(N, N);
for i = 1:N
for j = 1:M
loop_z_prime = z_prime(i);
loop_upper_z = upper_z(j);
loop_lower_z = lower_z(j);
% Define the integrand as a function handle
integrand = @(z) Kernel_handle(z, loop_z_prime);
% Integrate using the defined function handle
Z(i,j) = integral(integrand, loop_lower_z, loop_upper_z);
end
end
toc
Elapsed time is 0.501875 seconds.
disp(Z)
1.0e+02 * 1.3037 - 2.4675i 1.1676 + 7.6634i 0.8191 + 0.6541i 1.1676 + 7.6634i 1.3037 - 2.4675i 1.1676 + 7.6634i 0.8191 + 0.6541i 1.1676 + 7.6634i 1.3037 - 2.4675i
Refer to the following references for further help.
  1. https://www.mathworks.com/help/matlab/ref/integral.html?s_tid=doc_ta#btbbkta-3
  2. https://www.mathworks.com/help/matlab/matlab_prog/creating-a-function-handle.html
Hope this answers your query.

更多回答(1 个)

Madeeha
Madeeha 2024-9-3

>>a=5

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