how to mirror data and then plot it?
信息
This question is locked. 请重新打开它进行编辑或回答。
显示 更早的评论
x =0:1:15;
y = tan(x);
plot(x,y)
i hv to mirror data and then plot also .how to do it
9 个评论
ramya
2024-8-8
So I understand that you want to mirror along the middle.
Thus
x = 0:1:15;
y = tan(x);
x_new = x;
x_mirrored = fliplr(x_new);
and
y_new = tan(x_mirrored);
Thus the plot obtained will be
figure;
plot(x_new, y_new, 'b', 'DisplayName', 'Symmetric Data');
legend;
xlabel('x');
ylabel('tan(x)');
title('Symmetric Data Plot');
Let me know if this is what was desired.
Aniket
2024-8-8
Something like this ?
a= [1 2 3 4 5 6 7 8 9 10] ;
b=[0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.2 0.3] ;
ix=fix(numel(a)/2);
c=[b(1:ix) fliplr(b(1:ix))];
plot(a,c)
The above keeps the same number of elements as the original; to do your precise example reduces the number of points by one for an even number...your choice as to which would be the intent/need.
You still haven't precisely defined "symmetry about what?" for the original -- about the minimum, perhaps? That kind of thing may be very dependent upon just what the real application is, not just specifically for the one given example.
But a clear and unambiguous definition of just what "symmetrical" means to you is mandatory...
ramya
2024-8-8
dpb
2024-8-8
In that case, don't start a new and seemingly unrelated thread...what's wrong with the Answer @Cris LaPierre provided you there? Why don't you amplify in depth what "symmetry" is supposed to mean for the given data which look anything but as given?
It's not possible to answer a question when the specifications for the solution definition aren't clear...you may have a clear understanding of what you mean, but apparently nobody else here does...
I'm flagging this as duplicated to keep the conversation in one place and as a courtesy to those who responded there with best efforts...
回答（0 个）
This question is locked.
类别
在 帮助中心 和 File Exchange 中查找有关 Programming 的更多信息
Locked:
2024-8-8
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
