Matlab Matrix: Eliminating Duplicate Entries

Hello, all, thanks for reading this post.
I have a problem with a point coordinate matrix I create. I output the matrix correctly, but one of the bugs in the program I inherited is every point after point 1 is duplicated. I looks something like:
0 0 0
0 0 3.0000
0 0 3.0000
0 1.4225 4.8659
0 1.4225 4.8659
0 -1.4269 4.8520
0 -1.4269 4.8520
1.1125 2.3073 6.0264
1.1125 2.3073 6.0264
-1.1160 2.3007 6.0177
-1.1160 2.3007 6.0177
1.1086 -2.3144 6.0039
1.1086 -2.3144 6.0039
-1.1120 -2.3078 5.9953
-1.1120 -2.3078 5.9953
for 8 coordinates (and 7 connections, as this is a binary tree).
Is there a way to output a new point coordinate matrix where I have 8 rows, and no duplicate points?
Thanks
Edit: unique(A,'rows') will work in my case (because the point coordinates are exactly the same), but when I use it it outputs the coordinates in alpha-numeric order. Is there a way to output the coordinates in their original order, minus the duplicates?

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unique(A,'rows')

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Note: if the above does not work, then the duplicates might not be *exact* duplicates -- e.g., the difference between them might be on the order of 1E-15 . If that is the case, you might need a different strategy.
Actually, unique(A,'rows') will work in my case (because the point coordinates are exactly the same), but when I use it it outputs the coordinates in alpha-numeric order. Is there a way to output the coordinates in their original order, minus the duplicates?
Yes. the output of unique() is sorted. You can do this to get the original order.
a=[9 8 9 7 6 7 5 4 8];
[b,ind]=unique(a,'first');
b=a(sort(ind));
Thanks, I tried that but when I did it it only sorted the first column and deleted the other three (making it a 1 by 8 array, effectively deleting the y and z coordinates).
What I mean is: it turned:
0 0 0
0 0 3.0000
0 0 3.0000
0 1.4225 4.8659
0 1.4225 4.8659
0 -1.4269 4.8520
0 -1.4269 4.8520
1.1125 2.3073 6.0264
1.1125 2.3073 6.0264
-1.1160 2.3007 6.0177
-1.1160 2.3007 6.0177
1.1086 -2.3144 6.0039
1.1086 -2.3144 6.0039
-1.1120 -2.3078 5.9953
-1.1120 -2.3078 5.9953
into:
0
0
0
0
1.1125
-1.1160
1.1086
-1.1120
Which is right for the x coordinates. Is it possible to extend the sort to the entire matrix, not just the first column?
Using the indexing I suggested in my answer would deal with these issues much more readily...
It's a matter of selecting all the columns.
b=a(sort(ind),:)

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A(1:2:end,:)
This does not have the problem with comparing nearly equal quantities, but it does assume that the second row of each pair is acceptable

1 个评论

Thanks, this worked exactly as I wanted to! Sorry I didn't see your comment until now, but this worked exactly as I needed it to.

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