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Resolving array indices must be positive integers or logical values error?

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Emily
Emily 2024-8-23，15:43
编辑： Shivam Gothi 2024-8-23，16:14
I am running this piece of code:
fold_name=pwd; a=regexp(fold_name,'/'); fold_name=fold_name(a(end)+1:end);
my pwd is the following: 'C:\testsamples'
when running the first two pieces of code, I do not get any error. When running the third piece I get this error:
"Array indices must be positive integers or logical values."
Any ideas as to why?
  1 个评论
Stephen23
Stephen23 2024-8-23，15:58
Ran in:
"Any ideas as to why?"
Beacuse the character / does not exist anywhere in your text, so a is empty:
fold_name = 'C:\testsamples';
a = regexp(fold_name,'/')
a = []

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回答（2 个）

Star Strider
Star Strider 2024-8-23，15:54
Ran in:
If you just want the string data after the slant, some optionos are —
pwd = 'C:\testsamples'
pwd = 'C:\testsamples'
LastString = extractAfter(pwd, '\')
LastString = 'testsamples'
BothStrings = strsplit(pwd, '\')
BothStrings = 1x2 cell array
{'C:'} {'testsamples'}
Another option is the fileparts function.
.
Shivam Gothi
Shivam Gothi 2024-8-23，16:13
编辑：Shivam Gothi 2024-8-23，16:14
Hello,
From the above code, it seems that you are trying to access the name “testsamples” from the fold_name = 'C:\testsamples'.
The function “regexp(str,expression)” returns the starting index of each substring of str that matches the character patterns specified by the regular expression.
In the code, '/' was used instead of '\' in the 'expression' field of the function mentioned above. This seems to result in 'a' being an empty array, which is then used to index into “fold_name”. I believe this might be causing the error. I have attached a screenshot of the updated code along with the result obtained. Could you please confirm if this is the desired outcome?
Additionally, please refer to the following link to learn more about the regexp() function."
https://in.mathworks.com/help/matlab/ref/regexp.html
I hope this solves the issue.

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