While loop for a menu
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options=menu('Options','Report Quadrants','Plot Data','Avg. Dist.','Max Dist.','Print Ascii','Exit Program')
while (true) options<6
options=menu('Options','Report Quadrants','Plot Data','Avg. Dist.','Max Dist.','Print Ascii','Exit Program')
for options=6
break
end
end
I'm trying to create a while loop for a menu in order to have it remain until "exit program" is selected from the options menu. Somethings incorrect because the options value goes to 0 after the first choice.
采纳的回答
Nobel Mondal
2015-5-3
In my opinion, the proper way of doing this would be - using call-back functions. Please have a look if this documentation helps you. There are a few relevant examples as well.
doc uimenu
Please let me know, if this is not applicable for any specific requirement that you have.
更多回答（2 个）
Image Analyst
2015-5-4
You could do this:
buttonNumber = 1; % Initialize
while buttonNumber < 6
buttonNumber = menu('Options','Report Quadrants','Plot Data',...
'Avg. Dist.','Max Dist.','Print Ascii','Exit Program')
if buttonNumber == 6
break; % Get out of the loop
end
% else do stuff based on buttonNumber
end
Paulo Almeida
2017-11-13
0 个投票
Due to respect of this topic, i want to create a submenu inside one of the options, and when the user press "exit/back" ir returns t the previous menu (original one). It works just fine until i press "back" in the submenu option and it seems to enter in an infinite loop and it can't get out of the submenu.
1 个评论
Image Analyst
2017-11-13
Paulo, this link will solve your problems with your code https://blogs.mathworks.com/videos/2012/07/03/debugging-in-matlab/ Since only you have your code, not us, we can't solve your problem directly. But that link will definitely allow you to solve it yourself.
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