Determining electric field from electrostatic potential

17 次查看（过去 30 天）
Somnath
Somnath 2024-9-2
回答： Eliezer 2024-10-17
I am trying to determine Elecric field from 2D electrostatic potential. E = -grad (V); I have a 2D matrix of (V). When I am writing [Ex Ey]=-imgradient(V,'sobel') I am getting error as Error using '-' , too many arguments. Someone kindly help to correct it.

请先登录，再回答此问题。

采纳的回答

nick
nick 2024-9-2
Hi Somnath,
I noticed an issue in the code regarding the use of the '-' operator with the 'imgradient' function in MATLAB. To ensure correct functionality, the code should be adjusted as follows:
[Ex Ey]=-1*imgradient(V,'sobel')
You may refer to the following documentation to learn more about operators in MATLAB :
https://www.mathworks.com/help/matlab/matlab_prog/matlab-operators-and-special-characters.html
Hope this helps!
  3 个评论
显示 1更早的评论
nick
nick 2024-9-12
Ran in:
Hi Somnath,
Thanks for letting me know about the persistent error. I apologize the inconvenience it may have caused. You can instead of compute gradient of '-1*V' instesad of 'V' to resolve the error.
The 'imgradient' function is primarily used for image processing, as it returns the gradient magnitude of a 2-D image.
To determine the 2-D Electric field frim potential, V, you can instead use the fucntion 'gradient'. The function returns the N components of the gradient of F, where F is an array with N dimensions. Here's an example MATLAB script of the same:
V = rand(5, 5); % Example 2D potential matrix
% Calculate the gradient of V
[Ex, Ey] = gradient(-1*V);
% Display the results
figure;
quiver(Ex, Ey);
title('Electric Field from Potential');
xlabel('X-axis');
ylabel('Y-axis');
axis equal;
You can refer to the following documentations to learn more about 'imgraident' and 'gradient':
imgradient: https://www.mathworks.com/help/releases/R2024a/images/ref/imgradient.html
gradient: https://www.mathworks.com/help/matlab/ref/gradient.html
I hope this helps, and feel free to reach out if you have any more questions!

请先登录，再进行评论。

更多回答（2 个）

Shivam
Shivam 2024-9-3
Hi Somnath,
I see that you are encountring the error while calculating electric field from 2D electric potential.
In vector calculus notation, the electric field is given by the negative of the gradient of the electric potential, E = −grad V.
You can follow the below workaround to correctly calculate the Electric Field:
% Compute the gradient components
[Ex, Ey] = imgradient(V);
% The electric field is the negative gradient of the potential
Ex = -Ex;
Ey = -Ey;
I hope this resolves the issue.
Regards,
Shivam
Eliezer
Eliezer 2024-10-17
See more here:
Campo Elétrico

类别

在 Help Center 和 File Exchange 中查找有关 Image Data Workflows 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by